Search results
Create the page "Problem 1" on this wiki! See also the search results found.
Page title matches
- ...math> and <math>2n</math> have opposite parities, as the order of <math>2n-1</math> is one more than the order of <math>2n</math>, and the answer is <ma227 bytes (40 words) - 04:42, 16 February 2024
- ==Problem== {{JBMO box|year=1999|before=First Problem|num-a=2|five=}}1 KB (205 words) - 13:05, 30 March 2019
- {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #1]] and [[2001 AMC 10 Problems|2001 AMC 10 #3]]}} == Problem ==904 bytes (136 words) - 15:10, 15 July 2024
- ...0 AMC 12 Problems|2000 AMC 12 #1]] and [[2000 AMC 10 Problems|2000 AMC 10 #1]]}} ==Problem==2 KB (320 words) - 18:37, 30 November 2024
- == Problem == From the problem statement, we construct the following diagram:2 KB (217 words) - 20:43, 2 February 2014
- ==Problem== ==Solution 1 (Linear Polynomials)==4 KB (670 words) - 12:03, 13 November 2023
- == Problem == What is <math>( - 1)^1 + ( - 1)^2 + \cdots + ( - 1)^{2006}</math>?468 bytes (70 words) - 09:40, 15 September 2017
- ...C 12B Problems|2005 AMC 12B #1]] and [[2005 AMC 10B Problems|2005 AMC 10B #1]]}} == Problem ==1 KB (179 words) - 12:53, 14 December 2021
- == Problem ==448 bytes (67 words) - 14:15, 23 March 2020
- ==Problem== ...x digits <math>4,5,6,7,8,9</math> in one of the six boxes in this addition problem?1 KB (191 words) - 16:12, 29 October 2016
- ==Problem== ...ath>a_n-g_n</math> is divisible by <math>m</math> for all integers <math>n>1</math>;5 KB (883 words) - 00:05, 2 June 2024
- == Problem == ...given by the [[binomial coefficient]] <math>{n \choose 6} = \frac{n\cdot(n-1)\cdot(n-2)\cdot(n-3)\cdot(n-4)\cdot(n-5)}{6\cdot5\cdot4\cdot3\cdot2\cdot1}<1 KB (239 words) - 10:54, 31 July 2023
- #REDIRECT [[2006 AMC 12A Problems/Problem 1]]45 bytes (5 words) - 09:55, 20 February 2016
- #REDIRECT [[2006 AMC 12A Problems/Problem 1]]45 bytes (5 words) - 13:46, 14 January 2016
- == Problem == [[Image:2005 AIME I Problem 1.png]]1 KB (213 words) - 12:17, 22 July 2017
- == Problem == == Solution 1==2 KB (250 words) - 22:56, 2 December 2024
- == Problem == [[Image:2004 AIME II Problem 1.png]]2 KB (329 words) - 22:20, 4 July 2013
- == Problem == Let <math>x</math>, <math>y</math> and <math>z</math> all exceed <math>1</math> and let <math>w</math> be a positive number such that <math>\log_x w4 KB (642 words) - 02:14, 17 August 2022
- == Problem == ...h>a_3\ldots</math> is an [[arithmetic progression]] with common difference 1, and <math>a_1+a_2+a_3+\ldots+a_{98}=137</math>.4 KB (576 words) - 14:33, 24 July 2024
- == Problem ==688 bytes (104 words) - 12:34, 22 July 2020
Page text matches
- === Proof 1 === <math>(a+b)^2=c^2+4\left(\frac{1}{2}ab\right)\implies a^2+2ab+b^2=c^2+2ab\implies a^2 + b^2=c^2</math>. {{Ha5 KB (885 words) - 22:03, 5 October 2024
- == Problem == pair O0=(9,9), O1=(1,1), O2=(3,1), O3=(1,3);2 KB (307 words) - 23:58, 17 November 2024
- ==Problem== <math>\textbf{(A)}\ 1 \qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textb1 KB (190 words) - 09:58, 16 June 2023
- ==Problem== ==Solution 1==1 KB (176 words) - 09:58, 16 June 2023
- ==Problem== <math>\textbf{(A) } -\frac{3}{8} \qquad \textbf{(B) } -\frac{1}{40} \qquad \textbf{(C) } 0 \qquad \textbf{(D) } \frac{3}{8} \qquad \textbf2 KB (257 words) - 09:57, 16 June 2023
- == Problem == A rectangular box has integer side lengths in the ratio <math>1: 3: 4</math>. Which of the following could be the volume of the box?1 KB (216 words) - 23:23, 5 September 2024
- == Problem == ..., replacing each occurrence of the digit <math>2</math> by the digit <math>1</math>. Star adds her numbers and Emilio adds his numbers. How much larger967 bytes (143 words) - 02:18, 27 June 2023
- == Problem == == Solution 1 ==2 KB (268 words) - 17:19, 27 September 2023
- == Problem == ...eft(\frac{1}{2}\right)=30 , \Rightarrow (+40)=70 , \Rightarrow \left(\frac{1}{2}\right)=\boxed{\textbf{(C) }35}</cmath>1 KB (169 words) - 13:59, 8 August 2021
- == Problem == A triangular array of <math>2016</math> coins has <math>1</math> coin in the first row, <math>2</math> coins in the second row, <math2 KB (395 words) - 22:29, 3 December 2024
- == Problem == ...er rectangle is one foot wide, and each of the two shaded regions is <math>1</math> foot wide on all four sides. What is the length in feet of the inner2 KB (337 words) - 13:56, 25 June 2023
- == Problem == filldraw((7,0)--(8,0)--(8,1)--(0,4)--(0,5)--(1,5)--cycle,gray(0.8));8 KB (1,016 words) - 23:17, 30 December 2023
- == Problem == Three distinct integers are selected at random between <math>1</math> and <math>2016</math>, inclusive. Which of the following is a correc2 KB (302 words) - 00:57, 18 October 2024
- == Problem == ...n a movie theater in a row containing <math>5</math> seats, numbered <math>1</math> to <math>5</math> from left to right. (The directions "left" and "ri2 KB (402 words) - 13:54, 25 June 2023
- ...tp://euclidlab.org/programs/archimedean-challenge/1 Archimedean Challenge #1] * [https://www.hardestmathproblem.org Hardest Math Problem] math contest for grades 5-8 with great prizes.7 KB (805 words) - 08:26, 17 November 2024
- ...duate or undergraduate mathematics students. The weeks break down into a 2-1-2 schedule: We start with two weeks of Root Class, which consists of a gall ...ctures and providing proofs. Classes include independent and collaborative problem solving as well as lots of laughter; in this way, students learn creative a5 KB (706 words) - 22:49, 29 January 2024
- ...cluding Art of Problem Solving, the focus of MATHCOUNTS is on mathematical problem solving. Students are eligible for up to three years, but cannot compete be ...rint</u>: 1-1.5 (School/Chapter), 2-2.5 (State/National)<br><u>Target:</u> 1.5 (School), 2 (Chapter), 2-2.5 (State/National)}}10 KB (1,504 words) - 13:10, 1 December 2024
- ...wo areas of math contests: Grade School (Grades 3, 4, 5, 6, 7, 8 + Algebra 1) and High School (Regional and State Finals). The contest is given in-school May 1-15. Each school sets its own testing date and time within these guidelines.8 KB (1,182 words) - 13:26, 3 April 2024
- '''Art of Problem Solving''' ('''AoPS''') is an educational resources company founded by [[Ri ...atics]]. As time goes on, AoPS is also reaching out to students of other [[problem-solving]] disciplines, including [[informatics]], [[physics]], [[programmin5 KB (658 words) - 09:03, 3 November 2024
- ...idual articles often have sample problems and solutions for many levels of problem solvers. Many also have links to books, websites, and other resources rele ...ates. [http://www.artofproblemsolving.com/Classes/AoPS_C_PSeries.php AoPS Problem Series].16 KB (2,192 words) - 22:06, 19 July 2024