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  • <cmath>20-21-29</cmath> <cmath>21-72-75 = (7-24-25)*3</cmath>
    6 KB (943 words) - 09:44, 17 January 2025
  • == Problem == ...ing this, we can say that <math>11 + 12 \cdots + 20 = 155</math> and <math>21 + \cdots +30 =255</math> and so on. This is a quick way to get to the point
    2 KB (395 words) - 22:29, 3 December 2024
  • ...administered by the [[American Mathematics Competitions]] (AMC). [[Art of Problem Solving]] (AoPS) is a proud sponsor of the AMC. ...-3|breakdown=<u>Problem 1-5</u>: 1<br><u>Problem 6-20</u>: 2<br><u>Problem 21-25</u>: 3}}
    4 KB (636 words) - 21:50, 17 January 2025
  • ...administered by the [[American Mathematics Competitions]] (AMC). [[Art of Problem Solving]] (AoPS) is a proud sponsor of the AMC! ...|breakdown=<u>Problem 1-10</u>: 2<br><u>Problem 11-20</u>: 3<br><u>Problem 21-25</u>: 4}}
    4 KB (529 words) - 08:01, 24 July 2024
  • == Problem 38== and add this result to the fourth integer. Thus the numbers <math>29, 23, 21</math>, and <math>17</math> are obtained. One of the original integers is:
    1 KB (200 words) - 22:35, 28 August 2020
  • * <math>21! = 51090942171709440000</math> ([[2007 iTest Problems/Problem 6|Source]])
    10 KB (809 words) - 15:40, 17 March 2024
  • ...ve results. Examples include the [[Monty Hall paradox]] and the [[birthday problem]]. Probability can be loosely defined as the chance that an event will hap * [[2006_AMC_10B_Problems/Problem_17 | 2006 AMC 10B Problem 17]]
    4 KB (590 words) - 10:52, 28 September 2024
  • ...former). Lop off the ending 0's and repeat. 1238 - 28 ==> 1210 ==> 121 - 21 ==> 100 ==> 1 NOPE. Works in general with numbers that are relatively pr * [[2000 AMC 8 Problems/Problem 11]]
    10 KB (1,572 words) - 21:11, 22 September 2024
  • ...ng may lead to a quick solution is the phrase "not" or "at least" within a problem statement. ''[[2006 AMC 10A Problems/Problem 21 | 2006 AMC 10A Problem 21]]: How many four-digit positive integers have at least one digit that is a
    8 KB (1,192 words) - 16:20, 16 June 2023
  • ([[2006 AMC 12A Problems/Problem 16|Source]]) ([[2006 AMC 12A Problems/Problem 21|Source]])
    9 KB (1,510 words) - 18:56, 16 January 2025
  • D((-1,21/5)--(7,3/5)); ...latively prime integers, find <math> p+q. </math> ([[2005 AIME II Problems/Problem 15|Source]])
    5 KB (892 words) - 20:52, 1 May 2021
  • ...the two preceding it. The first few terms are <math>1, 1, 2, 3, 5, 8, 13, 21, 34, 55,...</math>. ...iv style="text-align:right">([[2000 AMC 12 Problems/Problem 4|2000 AMC 12, Problem 4]])</div>
    7 KB (1,111 words) - 13:57, 24 June 2024
  • == Problem == It is often easier to first draw a diagram for such a problem.
    4 KB (691 words) - 17:38, 19 September 2021
  • ...5</math> implies <math>z_0</math> is even. QED [Oops, this doesn't work. 21 (or <math>3^4 = 81</math>) are equal to <math>1\mod 5</math> and not even.. ...s for any given Diophantine equations. This is known as [[Hilbert's tenth problem]]. The answer, however, is no.
    9 KB (1,434 words) - 00:15, 4 July 2024
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AMC 10B Problems/Problem 1]]
    2 KB (182 words) - 20:57, 23 January 2021
  • ...contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AMC 12B Problems/Problem 1 | Problem 1]]
    2 KB (210 words) - 23:06, 6 October 2014
  • ...A number of '''Mock AMC''' competitions have been hosted on the [[Art of Problem Solving]] message boards. They are generally made by one community member ...amous theorems and formulas and see if there's any way you can make a good problem out of them.
    51 KB (6,175 words) - 20:41, 27 November 2024
  • * <math>43 \equiv 22 \pmod{7}</math> because <math>\frac{43 - 22}{7} = \frac{21}{7} = 3</math>, which is an integer. === Sample Problem ===
    16 KB (2,410 words) - 13:05, 3 January 2025
  • <math>x^2 - 2x - 15 \equiv 0 \pmod{21}</math>. <math>(x - 5)(x + 3) \equiv 0 \pmod{21}</math>.
    14 KB (2,317 words) - 18:01, 29 October 2021
  • ...k contains the full set of test problems. The rest contain each individual problem and its solution. * [[2006 AMC 10A Problems/Problem 1]]
    2 KB (180 words) - 17:06, 6 October 2014

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