Search results
Create the page "Problem 28" on this wiki! See also the search results found.
Page title matches
- ==Problem== [[Image:1995_12_AMC-28.png|left]] By the [[Pythagorean Theorem]] on <math>\triangle OBB_1</math>,3 KB (510 words) - 18:12, 8 August 2024
- == Problem ==4 KB (662 words) - 23:51, 2 October 2023
- == Problem ==4 KB (607 words) - 11:25, 3 October 2023
- ==Problem==785 bytes (121 words) - 11:52, 5 July 2013
- ==Problem== ..._0, -b_0), (b_0, a_0), (-b_0, -a_0)</math> by the symmetry of the original problem.4 KB (679 words) - 16:21, 26 July 2021
- ==Problem==3 KB (545 words) - 09:21, 16 September 2022
- ==Problem==4 KB (657 words) - 01:54, 20 March 2024
- ==Problem==2 KB (327 words) - 18:03, 9 June 2017
- == Problem ==1 KB (193 words) - 14:00, 1 August 2016
- == Problem ==2 KB (282 words) - 20:14, 2 March 2019
- == Problem ==2 KB (284 words) - 20:12, 10 February 2019
- ==Problem==2 KB (277 words) - 11:44, 5 July 2013
- == Problem ==764 bytes (146 words) - 01:33, 15 September 2014
- ==Problem== ...''' [[2006 iTest Problems/Problem U9|U9]] '''•''' [[2006 iTest Problems/Problem U10|U10]]}}2 KB (222 words) - 20:20, 2 December 2018
- ==Problem==884 bytes (139 words) - 20:42, 16 April 2014
- ==Problem==1 KB (220 words) - 18:45, 20 November 2014
- == Problem ==723 bytes (112 words) - 00:40, 16 August 2023
- ==Problem== ...= (4,3)</math>, <math>DF=a</math>, and <math>AD=b</math>. As stated in the problem, the <math>x</math>-intercept <math>DF=a</math> is a positive prime number,2 KB (312 words) - 06:58, 28 September 2023
- == Problem ==1 KB (184 words) - 09:14, 1 August 2016
- == Problem ==799 bytes (129 words) - 00:53, 16 August 2023
Page text matches
- ...ypically contain a squared term such as <math>(x-3)^2</math>. However, the problem may be posed as to convert from an expanded form to a factored perfect squa <math>x^2+2x=28 </math> solve for x2 KB (422 words) - 15:20, 5 March 2023
- * <math>28! = 304888344611713860501504000000</math> ([[2007 iTest Problems/Problem 6|Source]])10 KB (809 words) - 15:40, 17 March 2024
- ...GREAT in binary). Here's one that works. 12348 - 28 ==> 12320 ==> 1232 +28 ==> 1260 ==> 126 + 14 ==> 14 YAY! * [[2000 AMC 8 Problems/Problem 11]]10 KB (1,572 words) - 21:11, 22 September 2024
- ...ng may lead to a quick solution is the phrase "not" or "at least" within a problem statement. ''[[2006 AMC 10A Problems/Problem 21 | 2006 AMC 10A Problem 21]]: How many four-digit positive integers have at least one digit that is8 KB (1,192 words) - 16:20, 16 June 2023
- == Problem == ...it deleted. Now, we know that <math>N<1000</math> (because this is an AIME problem). Thus, <math>N</math> has <math>1,</math> <math>2</math> or <math>3</math>4 KB (622 words) - 21:47, 13 October 2024
- == Problem 1 == [[2002 AMC 12A Problems/Problem 1|Solution]]12 KB (1,792 words) - 12:06, 19 February 2020
- == Problem 1 == [[2000 AMC 12 Problems/Problem 1|Solution]]13 KB (1,948 words) - 09:35, 16 June 2024
- == Problem 1 == [[2002 AMC 12B Problems/Problem 1|Solution]]10 KB (1,547 words) - 03:20, 9 October 2022
- == Problem 1 == [[2003 AMC 12B Problems/Problem 1|Solution]]13 KB (1,987 words) - 17:53, 10 December 2022
- == Problem == ...the Law of Cosines, <math>7^2=2^2+7^2-2(7)(2)\cos{\theta} \rightarrow 0=4-28\cos{\theta} \rightarrow \cos{\theta}=\frac{1}{7}</math>. In <math>\triangle2 KB (299 words) - 14:29, 5 July 2022
- == Problem == ...>20</math> or greater, so there is a total probability of <math>\dfrac{14}{28}=\boxed{\textbf{(D) }\frac{1}{2}}</math>.4 KB (607 words) - 14:16, 23 June 2024
- ==Problem 1== [[2006 AMC 10A Problems/Problem 1|Solution]]13 KB (2,028 words) - 15:32, 22 March 2022
- == Problem == MP("II", (8,-28), (0,0));3 KB (424 words) - 09:14, 17 December 2021
- ==Problem 1== [[1991 AJHSME Problems/Problem 1|Solution]]17 KB (2,246 words) - 12:37, 19 February 2020
- == Problem == *Person 1: <math>\frac{9 \cdot 6 \cdot 3}{9 \cdot 8 \cdot 7} = \frac{9}{28}</math>4 KB (628 words) - 10:28, 14 April 2024
- == Problem == pair C1 = (-10,0), C2 = (4,0), C3 = (0,0), H = (-10-28/3,0), T = 58/7*expi(pi-acos(3/7));4 KB (693 words) - 12:03, 28 December 2021
- == Problem == ...h>n(n + 7)</math> for some positive integer <math>n</math>. When <math>n = 28</math>, this product is <math>980</math>, and since AIME answers are nonneg8 KB (1,249 words) - 20:25, 20 November 2024
- == Problem == ...assign to <math>(0,1,0)</math>. (We will see how this correlates with the problem.) Then define for each lattice point <math>(i,j)</math> its triplet thus:5 KB (897 words) - 23:21, 28 July 2022
- == Problem == ...and are left with <math>c = 2</math>, so our triangle has area <math>\sqrt{28 \cdot 18 \cdot 8 \cdot 2} = 24\sqrt{14}</math> and so the answer is <math>25 KB (906 words) - 22:15, 6 January 2024
- == Problem == ...\tan\angle{B}=\frac{56}{33}</math> so <math>BJ=\frac{33}{56}*6x=\frac{99x}{28}</math>.14 KB (2,340 words) - 15:38, 21 August 2024