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  • <cmath>20-21-29</cmath> * [[2006_AIME_I_Problems/Problem_1 | 2006 AIME I Problem 1]]
    6 KB (943 words) - 09:44, 17 January 2025
  • == Problem 38== and add this result to the fourth integer. Thus the numbers <math>29, 23, 21</math>, and <math>17</math> are obtained. One of the original integ
    1 KB (200 words) - 22:35, 28 August 2020
  • * <math>29! = 8841761993739701954543616000000</math> ([[2007 iTest Problems/Problem 6|Source]])
    10 KB (809 words) - 15:40, 17 March 2024
  • * Compute some examples, for example find <math>3^{31} \pmod{7}, 29^{25} \pmod{11}</math>, and <math>128^{129} \pmod{17}</math>, and check your ...hat is the units digit of <math>k^2 + 2^k</math>? ([[2008 AMC 12A Problems/Problem 15]])
    16 KB (2,660 words) - 22:42, 28 August 2024
  • ===Divisibility Rule for 29=== [[Divisibility rules/Rule for 29 proof | Proof]]
    10 KB (1,572 words) - 21:11, 22 September 2024
  • ([[University of South Carolina High School Math Contest/1993 Exam/Problem 29|Source]]) ([[2006 AIME I Problems/Problem 14|Source]])
    6 KB (1,003 words) - 23:02, 19 May 2024
  • ([[University of South Carolina High School Math Contest/1993 Exam/Problem 29|Source]]) ([[Mock AIME 4 2006-2007 Problems/Problem 15|Source]])
    4 KB (658 words) - 15:19, 28 April 2024
  • ==Problem== Notice <math>2001 = 3 * 29 * 23</math>, so we can just maximize this with <math>667 * 3 * 1</math>, wh
    2 KB (320 words) - 18:37, 30 November 2024
  • == Problem 1 == [[2006 AIME I Problems/Problem 1|Solution]]
    7 KB (1,173 words) - 02:31, 4 January 2023
  • == Problem == ...its leftmost [[digit]] is deleted, the resulting integer is <math>\frac{1}{29}</math> of the original integer.
    4 KB (622 words) - 21:47, 13 October 2024
  • ==Problem 1== [[2021 JMC 10 Problems/Problem 1|Solution]]
    12 KB (1,784 words) - 15:49, 1 April 2021
  • == Problem 1 == ...} 0.029 \qquad \text{(C) } 0.29 \qquad \text{(D) } 2.9 \qquad \text{(E) } 29</math>
    13 KB (1,953 words) - 23:31, 25 January 2023
  • == Problem 1 == [[2000 AMC 12 Problems/Problem 1|Solution]]
    13 KB (1,948 words) - 09:35, 16 June 2024
  • == Problem 1 == [[2005 AMC 12B Problems/Problem 1|Solution]]
    12 KB (1,781 words) - 13:59, 19 July 2024
  • == Problem 10 == <math>\mathrm{(A)} 29 \qquad \mathrm{(B)} 55 \qquad \mathrm{(C)} 85 \qquad \mathrm{(D)} 133 \qqua
    1 KB (204 words) - 06:10, 5 November 2024
  • == Problem == \textbf{(B)}\ \frac {29}{2} \qquad
    5 KB (786 words) - 10:36, 19 May 2024
  • ==Problem 1== [[2006 AMC 10A Problems/Problem 1|Solution]]
    13 KB (2,028 words) - 15:32, 22 March 2022
  • == Problem == <math>\textbf{(A) } 29\qquad\textbf{(B) } 42\qquad\textbf{(C) } 45\qquad\textbf{(D) } 47\qquad\tex
    3 KB (533 words) - 23:24, 23 October 2024
  • ==Problem 1== [[1991 AJHSME Problems/Problem 1|Solution]]
    17 KB (2,246 words) - 12:37, 19 February 2020
  • == Problem == ...</math>. There are fifteen of these (<math>2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43</math> and <math>47</math>) so there are <math> {15 \choose
    2 KB (249 words) - 08:37, 23 January 2024

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