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- == Problem == ...y of South Carolina High School Math Contest/1993 Exam/Problem 28|Previous Problem]]2 KB (219 words) - 08:57, 31 August 2012
- ==Problem==99 bytes (12 words) - 22:19, 19 December 2019
- ==Problem==2 KB (371 words) - 13:33, 15 January 2023
- == Problem ==3 KB (522 words) - 10:39, 3 October 2023
- ==Problem==1 KB (173 words) - 18:52, 30 December 2020
- == Problem == ...3(99-12)=29</math> multiples of three in that range, so there are <math>88-29=59</math> non-multiples, and <math>3+14+59=76</math>, which is <math>\fbox{2 KB (285 words) - 18:25, 25 September 2020
- == Problem==907 bytes (132 words) - 23:54, 29 January 2019
- ==Problem==4 KB (614 words) - 19:09, 12 September 2022
- ==Problem== ...imal expansion only consists of <math>0</math>'s and <math>1</math>'s. The problem is equivalent to finding the number of super-special numbers necessary to a2 KB (245 words) - 12:11, 9 August 2013
- ==Problem== Working with the second part of the problem first, we know that <math>3n</math> has <math>30</math> divisors. We try t5 KB (828 words) - 04:52, 26 October 2023
- ==Problem==3 KB (351 words) - 02:25, 20 March 2024
- == Problem == ...elopes addressed does not matter, because it stays constant throughout the problem.2 KB (327 words) - 23:59, 11 October 2020
- ==Problem==1 KB (159 words) - 11:44, 5 July 2013
- == Problem ==1 KB (205 words) - 20:15, 20 December 2024
- == Problem ==2 KB (252 words) - 19:25, 2 October 2018
- == Problem ==1 KB (167 words) - 07:44, 1 January 2024
- ==Problem==628 bytes (100 words) - 21:23, 4 June 2018
- ==Problem==811 bytes (132 words) - 13:38, 23 September 2024
- == Problem ==714 bytes (114 words) - 00:40, 16 August 2023
- ==Problem==3 KB (395 words) - 08:19, 28 September 2023
Page text matches
- <cmath>20-21-29</cmath> * [[2006_AIME_I_Problems/Problem_1 | 2006 AIME I Problem 1]]6 KB (943 words) - 09:44, 17 January 2025
- == Problem 38== and add this result to the fourth integer. Thus the numbers <math>29, 23, 21</math>, and <math>17</math> are obtained. One of the original integ1 KB (200 words) - 22:35, 28 August 2020
- * <math>29! = 8841761993739701954543616000000</math> ([[2007 iTest Problems/Problem 6|Source]])10 KB (809 words) - 15:40, 17 March 2024
- * Compute some examples, for example find <math>3^{31} \pmod{7}, 29^{25} \pmod{11}</math>, and <math>128^{129} \pmod{17}</math>, and check your ...hat is the units digit of <math>k^2 + 2^k</math>? ([[2008 AMC 12A Problems/Problem 15]])16 KB (2,660 words) - 22:42, 28 August 2024
- ===Divisibility Rule for 29=== [[Divisibility rules/Rule for 29 proof | Proof]]10 KB (1,572 words) - 21:11, 22 September 2024
- ([[University of South Carolina High School Math Contest/1993 Exam/Problem 29|Source]]) ([[2006 AIME I Problems/Problem 14|Source]])6 KB (1,003 words) - 23:02, 19 May 2024
- ([[University of South Carolina High School Math Contest/1993 Exam/Problem 29|Source]]) ([[Mock AIME 4 2006-2007 Problems/Problem 15|Source]])4 KB (658 words) - 15:19, 28 April 2024
- ==Problem== Notice <math>2001 = 3 * 29 * 23</math>, so we can just maximize this with <math>667 * 3 * 1</math>, wh2 KB (320 words) - 18:37, 30 November 2024
- == Problem 1 == [[2006 AIME I Problems/Problem 1|Solution]]7 KB (1,173 words) - 02:31, 4 January 2023
- == Problem == ...its leftmost [[digit]] is deleted, the resulting integer is <math>\frac{1}{29}</math> of the original integer.4 KB (622 words) - 21:47, 13 October 2024
- ==Problem 1== [[2021 JMC 10 Problems/Problem 1|Solution]]12 KB (1,784 words) - 15:49, 1 April 2021
- == Problem 1 == ...} 0.029 \qquad \text{(C) } 0.29 \qquad \text{(D) } 2.9 \qquad \text{(E) } 29</math>13 KB (1,953 words) - 23:31, 25 January 2023
- == Problem 1 == [[2000 AMC 12 Problems/Problem 1|Solution]]13 KB (1,948 words) - 09:35, 16 June 2024
- == Problem 1 == [[2005 AMC 12B Problems/Problem 1|Solution]]12 KB (1,781 words) - 13:59, 19 July 2024
- == Problem 10 == <math>\mathrm{(A)} 29 \qquad \mathrm{(B)} 55 \qquad \mathrm{(C)} 85 \qquad \mathrm{(D)} 133 \qqua1 KB (204 words) - 06:10, 5 November 2024
- == Problem == \textbf{(B)}\ \frac {29}{2} \qquad5 KB (786 words) - 10:36, 19 May 2024
- ==Problem 1== [[2006 AMC 10A Problems/Problem 1|Solution]]13 KB (2,028 words) - 15:32, 22 March 2022
- == Problem == <math>\textbf{(A) } 29\qquad\textbf{(B) } 42\qquad\textbf{(C) } 45\qquad\textbf{(D) } 47\qquad\tex3 KB (533 words) - 23:24, 23 October 2024
- ==Problem 1== [[1991 AJHSME Problems/Problem 1|Solution]]17 KB (2,246 words) - 12:37, 19 February 2020
- == Problem == ...</math>. There are fifteen of these (<math>2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43</math> and <math>47</math>) so there are <math> {15 \choose2 KB (249 words) - 08:37, 23 January 2024