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- ==Problem== {{AMC12 box|year=2016|ab=A|num-b=2|num-a=4}}2 KB (257 words) - 09:57, 16 June 2023
- == Problem ==1 KB (249 words) - 12:05, 24 January 2024
- == Problem == ...ece of length <math>k_i</math> from the end of leg <math>L_i \; (i = 1,2,3,4)</math> and still have a stable table?7 KB (1,276 words) - 19:51, 6 January 2024
- == Problem == ...at the right end of the decimal representation of the product <math> 1!2!3!4!\cdots99!100!. </math> Find the remainder when <math> N </math> is divided2 KB (353 words) - 21:56, 27 September 2024
- == Problem == ...t the grocery store. The prices of the items are <math>7.99</math>, <math>4.99</math>, <math>2.99</math>, <math>1.99</math>, and <math>0.99</math>. Ma1 KB (152 words) - 15:11, 8 December 2013
- {{duplicate|[[2005 AMC 12B Problems|2005 AMC 12B #4]] and [[2005 AMC 10B Problems|2005 AMC 10B #6]]}} == Problem ==1 KB (197 words) - 13:16, 14 December 2021
- == Problem == ...sect at a right angle at <math>E</math> . Given that <math> BE = 16, DE = 4, </math> and <math> AD = 5 </math>, find <math> CE </math>.1 KB (177 words) - 01:14, 26 November 2020
- #REDIRECT [[2006 AIME I Problems/Problem 4]]44 bytes (5 words) - 11:03, 28 June 2009
- == Problem ==3 KB (377 words) - 17:36, 1 January 2024
- #REDIRECT [[2006 AMC 12A Problems/Problem 4]]45 bytes (5 words) - 09:58, 20 February 2016
- ...lems|2006 AMC 12A #4]] and [[2006 AMC 10A Problems/Problem 4|2006 AMC 10A #4]]}} == Problem ==2 KB (257 words) - 10:20, 2 January 2022
- == Problem == ...erfect square]] strictly between <math>(n + 3)^2 + 5</math> and <math>(n + 4)^2 + 5</math>. Thus, if the number of columns is <math>n</math>, the numbe8 KB (1,249 words) - 20:25, 20 November 2024
- == Problem == ...h> and <math>(0,y)</math>. Because the segment has length 2, <math>x^2+y^2=4</math>. Using the midpoint formula, we find that the midpoint of the segmen3 KB (532 words) - 08:22, 11 July 2023
- == Problem == ...>-digit number, for a total of <math>(2^1 - 2) + (2^2 - 2) + (2^3 -2) + (2^4 - 2) = 22</math> such numbers (or we can list them: <math>AB, BA, AAB, ABA,3 KB (508 words) - 00:16, 19 January 2024
- ==Problem== <cmath> AC = \sqrt{AB^2 + BC^2} = \sqrt{36 + 4} = \sqrt{40} = 2 \sqrt{10}. </cmath>11 KB (1,747 words) - 20:07, 8 December 2024
- == Problem ==2 KB (319 words) - 02:38, 16 January 2023
- == Problem == ...\frac{1}{1985} = 1</math>, where <math>X</math> is the area of the of the 4 triangles.3 KB (484 words) - 20:40, 2 March 2020
- == Problem == ...ve [[equation]]s gives us <math>6(x_1 + x_2 + x_3 + x_4 + x_5) = 6(1 + 2 + 4 + 8 + 16)</math> so <math>x_1 + x_2 + x_3 + x_4 + x_5 = 31</math>. Subtrac1 KB (212 words) - 15:25, 17 November 2019
- == Problem == ...of the region enclosed by the [[graph]] of <math>|x-60|+|y|=\left|\frac{x}{4}\right|.</math>2 KB (371 words) - 16:25, 13 February 2024
- == Problem == ...S is <math>1.</math> Similarly testing <math>1,-1,-1,1</math> yields <math>4</math> on the LHS and <math>0</math> on the RHS. It seems for every negativ2 KB (394 words) - 09:21, 27 January 2024
Page text matches
- B = (4, 3); C = (4, 0);5 KB (885 words) - 22:03, 5 October 2024
- == Problem == label("$s$",(-1.5,4));2 KB (307 words) - 23:58, 17 November 2024
- ==Problem== ...xtbf{(A)}\ 1 \qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 5</math>1 KB (190 words) - 09:58, 16 June 2023
- ==Problem== ...<math>$12.50</math> more than David, so we can write <math>$12.50\cdot (4+3)=$ 87.50.</math> Then the answer is <math>\boxed{\text{(C)}}.</math>1 KB (176 words) - 09:58, 16 June 2023
- ==Problem== {{AMC12 box|year=2016|ab=A|num-b=2|num-a=4}}2 KB (257 words) - 09:57, 16 June 2023
- == Problem == A rectangular box has integer side lengths in the ratio <math>1: 3: 4</math>. Which of the following could be the volume of the box?1 KB (216 words) - 23:23, 5 September 2024
- == Problem == filldraw(rectangle((1,1),(6,4)),gray(0.75));2 KB (337 words) - 13:56, 25 June 2023
- == Problem == filldraw((7,0)--(8,0)--(8,1)--(0,4)--(0,5)--(1,5)--cycle,gray(0.8));8 KB (1,016 words) - 23:17, 30 December 2023
- == Problem == ...{(A) }1 \qquad \textbf{(B) } 2 \qquad \textbf{(C) } 3 \qquad \textbf{(D) } 4\qquad \textbf{(E) } 5</math>2 KB (402 words) - 13:54, 25 June 2023
- * [[Noetic Learning Math Contest]] - semiannual problem solving contest for elementary and middle school students. [Grades 2-8] ....mathcon.org MathCON] hosts annual math competition for students in grades 4-12.5 KB (512 words) - 08:27, 17 November 2024
- * [https://www.hardestmathproblem.org Hardest Math Problem] math contest for grades 5-8 with great prizes. * [[Noetic Learning Math Contest]]: a popular problem-solving contest for students in grades 2-8.7 KB (805 words) - 08:26, 17 November 2024
- ....mathcon.org MathCON] hosts annual math competition for students in grades 4-12, with more than 200,000 participants since 2008. * [[Mathematical problem solving]]5 KB (608 words) - 08:32, 17 November 2024
- ...cluding Art of Problem Solving, the focus of MATHCOUNTS is on mathematical problem solving. Students are eligible for up to three years, but cannot compete be ...ics]]. The focus of MATHCOUNTS curriculum is in developing [[mathematical problem solving]] skills.10 KB (1,504 words) - 13:10, 1 December 2024
- ...of Mathematics offers two areas of math contests: Grade School (Grades 3, 4, 5, 6, 7, 8 + Algebra 1) and High School (Regional and State Finals). *2024 State FInals - Saturday 4/6/248 KB (1,182 words) - 13:26, 3 April 2024
- ...s problems and competition results are sometimes discussed in the [[Art of Problem Solving]] [http://www.artofproblemsolving.com/Forum/index.php?f=172 Alabama * 4. Lucy Xie - [[Louis Pizitz Middle School]]3 KB (386 words) - 20:23, 6 May 2023
- ...oal of MOEMS is to expose students to elementary methods of [[mathematical problem solving]]. ...ath Jams are designed to help PICOs learn new ways to teach [[mathematical problem solving]] to MOEMS students.2 KB (215 words) - 01:54, 18 November 2020
- ...9|breakdown=<u>Problem A/B, 1/2</u>: 7<br><u>Problem A/B, 3/4</u>: 8<br><u>Problem A/B, 5/6</u>: 9}} ...chool olympiads are, although they include more advanced mathematics. Each problem is graded on a scale of 0 to 10. The top five scorers (or more if there are4 KB (623 words) - 12:11, 20 February 2024
- ==Problem== Find the sum of the infinite series: <center><math>3+\frac{11}4+\frac 94 + \cdots + \frac{n^2+2n+3}{2^n}+\cdots</math>.</center>1 KB (193 words) - 20:13, 18 May 2021
- A more complex example is <math>\frac{x-8}{x+5}+4\ge 3</math>. \frac{x-8}{x+5}+4&\ge 312 KB (1,806 words) - 05:07, 19 June 2024
- The USAMTS is administered by the [[Art of Problem Solving Foundation]] with support and sponsorship by the [[National Securit ...gion=USA|type=Proof|difficulty=3-6|breakdown=<u>Problem 1-2</u>: 3-4<br><u>Problem 3-5</u>: 5-6}}4 KB (613 words) - 21:12, 15 October 2024