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• Sub-Problem 2
  1 KB (161 words) - 22:23, 28 November 2023
• Euc20197/Sub-Problem 2
  220 bytes (40 words) - 19:17, 22 March 2021
• Euc20197/Sub-Problem 1
  881 bytes (135 words) - 19:48, 22 March 2021
• Euc20198/Sub-Problem 2
  291 bytes (47 words) - 23:03, 22 March 2021
• Euc20205/Sub-Problem 2
  303 bytes (46 words) - 23:12, 22 March 2021
• Euc20205/Sub-Problem 1
  200 bytes (40 words) - 04:24, 31 March 2023

Page text matches

• 1970 IMO Problems/Problem 6
  <math>\mathcal{L}_1</math> of all the triangles, and a sub-list <math>\mathcal{L}_2</math> sub-list <math>\mathcal{L}_2</math> of all the acute triangles. We have that
  6 KB (1,054 words) - 18:09, 11 December 2024
• Partition of an interval
  ...n of an interval''' is a division of an [[interval]] into several disjoint sub-intervals. Partitions of intervals arise in [[calculus]] in the context of
  1 KB (178 words) - 20:34, 6 March 2022
• Harmonic series
  There are several sub-types of '''harmonic series'''.
  2 KB (334 words) - 20:52, 13 March 2022
• Limit
  :Let <math>f</math> be a function whose [[domain]] is a sub-interval of the real numbers and whose [[codomain]] is the set of reals. Fo
  7 KB (1,327 words) - 18:39, 28 September 2024
• 2005 AMC 12B Problems/Problem 25
  We divide the paths into two sub-cases. ...ertices, and that selection decides the remainder of the path. Thus, this sub-case has 2 possible paths.
  10 KB (1,840 words) - 15:01, 4 July 2024
• 2004 AIME II Problems/Problem 14
  Like this we get the value of "distinct" <math>n</math> by summing all the sub-values from the cases that we've solved.
  11 KB (1,857 words) - 12:57, 18 July 2024
• 1984 AIME Problems/Problem 5
  ...ting to exponents, we get <math>8^c=ab</math> and <math>4^k=(ab)^2</math>. Sub in the <math>8^c</math> to get <math>k=3c</math>. So now we have that <math
  8 KB (1,319 words) - 22:42, 6 March 2025
• 2001 AIME I Problems/Problem 14
  ...of 001's in the sequence. For each case, we will divide further into three sub-cases, based on the pattern of mail delivery for the last three houses. Sub-case 1: The last house that gets mail is the 17th house. Thus, we have the
  15 KB (2,728 words) - 15:36, 23 December 2024
• 1970 IMO Problems/Problem 4
  We consider two sub-cases corresponding to <math>p = </math> odd or <math>p = </math> Case 2.2.1: Take the sub-sub-case <math>2(3r^2 + 1) = \square</math> and
  10 KB (1,617 words) - 20:44, 2 December 2024
• 2000 AMC 12 Problems/Problem 21
  ...f area <math>S=\frac{2}{3}\times\frac{2}{3}=\frac{4}{9}</math>. The larger sub-triangle has area <math>T_1=\frac{\frac{2}{3}\times\frac{4}{3}}{2}=\frac{4}
  5 KB (804 words) - 01:22, 13 May 2024
• List of BBCodes
  <td><code>[sub]</code></td><td>Causes the text to become a subscript.</td>
  6 KB (1,152 words) - 18:29, 12 December 2022
• 2008 AIME I Problems/Problem 1
  Now we can sub in <math>30t=50g</math> by multiplying the first equation by <math>10</math
  2 KB (378 words) - 22:23, 19 December 2022
• Stabilizer
  The stabilizer of any set <math>A</math> is evidently a sub-monoid of <math>M</math>, as is the strict stabilizer. Also, if <math>a</m
  3 KB (531 words) - 18:47, 9 September 2008
• Euclid 2019/Problem 1
  This page consists of 3 sub-problems.
  227 bytes (23 words) - 22:44, 30 March 2023
• Ascending chain condition
  of sub-modules of <math>M</math> with the ordering of <math>M</math> satifies ACC,
  2 KB (314 words) - 18:00, 15 December 2018
• 2009 USAMO Problems/Problem 2
  ..._{2k-1}| \ge s_{2k-1} - 1 \ge 2k - 1</math>. We now show the following two sub-results: :''Sub-lemma (A)'': if <math>|P_{2k-1}| \ge k</math>, <math>-2k \not \in M_{2k}</m
  8 KB (1,444 words) - 03:44, 2 October 2015
• 2013 AIME II Problems/Problem 12
  ...member of the set <math>\{-20, 20, -13, 13\}</math>. It splits into three sub-cases: either no two are the same, exactly two are the same, or all three a <b>Sub-case 1.1:</b> No two are the same.
  8 KB (1,405 words) - 02:47, 26 November 2024
• 2015 AMC 10A Problems/Problem 22
  ...> three people are next to each other which is <math>\dbinom{8}{1}</math>. Sub-case <math>2:</math> two people are next to each other and the third person
  11 KB (1,724 words) - 15:29, 13 October 2024
• 2015 AMC 12A Problems/Problem 23
  .../math> by hand, we want to pull out the <math>1/4</math>, and then apply u-sub and our integration rules to find the answer.
  12 KB (1,981 words) - 18:33, 3 September 2023
• 2015 USAJMO Problems/Problem 1
  Sub case 1a: if <math>a + b</math> sum to <math>0</math> in this sequence, the ...>0</math> both have a negative/positive counter part, do the same thing in Sub case 1a; <math>(a_i, -a_i)</math> turning the whole sequence to <math>0</ma
  8 KB (1,405 words) - 20:13, 26 July 2022

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