Difference between revisions of "1981 AHSME Problems/Problem 24"
Alexwin0806 (talk | contribs) m (→Solution) |
Alexwin0806 (talk | contribs) (→Solution) |
||
| Line 22: | Line 22: | ||
<cmath>=\cos(n\theta) + i\sin(n\theta) + \cos(n\theta) - i\sin(n\theta)</cmath> | <cmath>=\cos(n\theta) + i\sin(n\theta) + \cos(n\theta) - i\sin(n\theta)</cmath> | ||
| − | <cmath>=2\cos(n\theta)</cmath> | + | <cmath>=\boxed{\textbf{2\cos(n\theta)}}</cmath> |
Which gives the answer <math>\boxed{\textbf{D}}</math> | Which gives the answer <math>\boxed{\textbf{D}}</math> | ||
Revision as of 21:27, 1 May 2020
Problem
If 
is a constant such that 
and 
, then for each positive integer 
, 
equals
Solution
Multiply both sides by 
and rearrange to 
. Using the quadratic equation, we can solve for . After some simplifying:
![\[x=\cos(\theta) + \sqrt{\cos^2(\theta)-1}\]](http://latex.artofproblemsolving.com/4/d/f/4dfaa96d4f48bb666eb8c48146e1492987ef6c2f.png)
![\[x=\cos(\theta) + \sqrt{(-1)(\sin^2(\theta))}\]](http://latex.artofproblemsolving.com/6/9/c/69c6dddc307c908580702605d7feffffbf3cbc9c.png)
![\[x=\cos(\theta) + i\sin(\theta)\]](http://latex.artofproblemsolving.com/e/9/5/e952a9c3624de3f2c1b1dab34054d82ca63ee950.png)
Substituting this expression in to the desired gives:
![\[(\cos(\theta) + i\sin(\theta))^n + (\cos(\theta) + i\sin(\theta))^{-n}\]](http://latex.artofproblemsolving.com/1/4/7/147b08fd15b530e18f6e3c39644bc552a3e5dcf4.png)
Using DeMoivre's Theorem:
![\[=\cos(n\theta) + i\sin(n\theta) + \cos(-n\theta) + i\sin(-n\theta)\]](http://latex.artofproblemsolving.com/1/0/a/10a4879a58d6eb32e0da94dfaf3552f7f04b2d80.png)
Because 
is even and 
is odd:
![\[=\cos(n\theta) + i\sin(n\theta) + \cos(n\theta) - i\sin(n\theta)\]](http://latex.artofproblemsolving.com/9/c/4/9c4ab1d8bcdb50a156082686378683e6c4732c1c.png)
\[=\boxed{\textbf{2\cos(n\theta)}}\] (Error compiling LaTeX. Unknown error_msg)
Which gives the answer 
