Difference between revisions of "2008 AMC 12A Problems/Problem 5"
(New page: ==Problem== Suppose that <math>\frac {2x}{3} - \frac {x}{6}</math> is an integer. Which of the following statements must be true about <math>x</math>? <math>\textbf{(A)}\ \text{It is ne...) |
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+ | {{duplicate|[[2008 AMC 12A Problems|2008 AMC 12A #5]] and [[2008 AMC 10A Problems/Problem 9|2008 AMC 10A #9]]}} | ||
==Problem== | ==Problem== | ||
Suppose that | Suppose that | ||
− | + | <cmath>\frac{2x}{3}-\frac{x}{6}</cmath> | |
− | < | ||
− | |||
is an integer. Which of the following statements must be true about <math>x</math>? | is an integer. Which of the following statements must be true about <math>x</math>? | ||
− | <math>\ | + | <math>\mathrm{(A)}\ \text{It is negative.}\\mathrm{(B)}\ \text{It is even, but not necessarily a multiple of 3.}\\mathrm{(C)}\ \text{It is a multiple of 3, but not necessarily even.}\\mathrm{(D)}\ \text{It is a multiple of 6, but not necessarily a multiple of 12.}\\mathrm{(E)}\ \text{It is a multiple of 12.}</math> |
− | \ | ||
− | \ | ||
− | \ | ||
− | ==Solution== | + | ==Solution== |
− | + | <cmath>\frac{2x}{3}-\frac{x}{6}\quad\Longrightarrow\quad\frac{4x}{6}-\frac{x}{6}\quad\Longrightarrow\quad\frac{3x}{6}\quad\Longrightarrow\quad\frac{x}{2}</cmath> | |
+ | For <math>\frac{x}{2}</math> to be an integer, <math>x</math> must be even, but not necessarily divisible by <math>3</math>. Thus, the answer is <math>\mathrm{(B)}</math>. | ||
− | ==See | + | ==See also== |
− | {{AMC12 box|year=2008|num-b=4|num-a=6|ab=A}} | + | {{AMC12 box|year=2008|ab=A|num-b=4|num-a=6}} |
+ | {{AMC10 box|year=2008|ab=A|num-b=8|num-a=10}} | ||
+ | {{MAA Notice}} |
Latest revision as of 02:17, 5 August 2021
- The following problem is from both the 2008 AMC 12A #5 and 2008 AMC 10A #9, so both problems redirect to this page.
Problem
Suppose that is an integer. Which of the following statements must be true about ?
Solution
For to be an integer, must be even, but not necessarily divisible by . Thus, the answer is .
See also
2008 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 4 |
Followed by Problem 6 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
2008 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.