Difference between revisions of "Arithmetic sequence"
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'''Proof''': Let the sequence have first term <math>a_1</math> and common difference <math>d</math>. Then using the above result, <cmath>\frac{y-x}{m-n} = \frac{(a_1 + (m - 1)d) - (a_1 + (n-1)d)}{m-n} = \frac{dm - dn}{m-n} = d,</cmath> as desired. <math>\square</math> | '''Proof''': Let the sequence have first term <math>a_1</math> and common difference <math>d</math>. Then using the above result, <cmath>\frac{y-x}{m-n} = \frac{(a_1 + (m - 1)d) - (a_1 + (n-1)d)}{m-n} = \frac{dm - dn}{m-n} = d,</cmath> as desired. <math>\square</math> | ||
− | Another lemma is that for any consecutive terms <math>a_{n-1}</math>, <math>a_n</math>, and <math>a_{n+1}</math> of an arithmetic sequence, then <math>a_n</math> is the arithmetic mean of <math>a_{n-1}</math> and <math>a_{n+1}</math>. In symbols, <math>a_n = \frac{a_{n-1} + a_{n+1}}{2}</math>. This is mostly used to perform substitutions. | + | Another lemma is that for any consecutive terms <math>a_{n-1}</math>, <math>a_n</math>, and <math>a_{n+1}</math> of an arithmetic sequence, then <math>a_n</math> is the arithmetic mean of <math>a_{n-1}</math> and <math>a_{n+1}</math>. In symbols, <math>a_n = \frac{a_{n-1} + a_{n+1}}{2}</math>. This is mostly used to perform substitutions, though it occasionally serves as a definition of arithmetic sequences. |
== Sum == | == Sum == |
Revision as of 12:33, 26 November 2021
In algebra, an arithmetic sequence, sometimes called an arithmetic progression, is a sequence of numbers such that the difference between any two consecutive terms is constant. This constant is called the common difference of the sequence.
For example, is an arithmetic sequence with common difference and is an arithmetic sequence with common difference ; however, and are not arithmetic sequences, as the difference between consecutive terms varies.
More formally, the sequence is an arithmetic progression if and only if . A similar definition holds for infinite arithmetic sequences. It appears most frequently in its three-term form: namely, that constants , , and are in arithmetic progression if and only if .
Contents
[hide]Properties
Because each term is a common distance from the one before it, every term of an arithmetic sequence can be expressed as the sum of the first term and a multiple of the common difference. Let be the first term, be the th term, and be the common difference of any arithmetic sequence; then, .
A common lemma is that given the th term and th term of an arithmetic sequence, the common difference is equal to .
Proof: Let the sequence have first term and common difference . Then using the above result, as desired.
Another lemma is that for any consecutive terms , , and of an arithmetic sequence, then is the arithmetic mean of and . In symbols, . This is mostly used to perform substitutions, though it occasionally serves as a definition of arithmetic sequences.
Sum
An arithmetic series is the sum of all the terms of an arithmetic sequence. All infinite arithmetic series diverge. As for finite series, there are two primary formulas used to compute their value.
The fist is that if an arithmetic series has first term , last term , and total terms, then its value is equal to .
Proof: Let the series be equal to , and let its common difference be . Then, we can write in two ways: Adding these two equations cancels all terms involving ; and so , as required.
The second is that if an arithmetic series has first term , common difference , and terms, it has value .
Proof: The final term has value . Then by the above formula, the series has value This completes the proof.
Problems
Here are some problems with solutions that utilize arithmetic sequences and series.
Introductory problems
- 2005 AMC 10A Problem 17
- 2006 AMC 10A Problem 19
- 2012 AIME I Problems/Problem 2
- 2004 AMC 10B Problems/Problem 10
- 2006 AMC 10A, Problem 9
- 2006 AMC 12A, Problem 12
Intermediate problems
- 2003 AIME I, Problem 2
- Find the roots of the polynomial , given that the roots form an arithmetic progression.