Difference between revisions of "1984 AJHSME Problem 9"

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(Please delete. The AJHSME didn't exist in 1984.)
 
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== Solution ==
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{{delete | AJHSME did not exist in 1984}}
This product simplifies to:
 
<cmath>\frac{1}{2} \cdot \frac{2}{3} \dots \frac{9}{10}.</cmath>
 
Numerators and denominators cancel to yield the answer: <math>\boxed{\text{(A)} \frac{1}{10}}.</math>
 

Latest revision as of 20:59, 3 May 2023

This article has been proposed for deletion. The reason given is: AJHSME did not exist in 1984.

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