Difference between revisions of "2024 AMC 8 Problems/Problem 17"
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Multiply by two to account for arrangements of colors to get <math>\fbox{E) 32}</math> ~ c_double_sharp | Multiply by two to account for arrangements of colors to get <math>\fbox{E) 32}</math> ~ c_double_sharp | ||
− | ==Video Solution 1 by Math-X (First understand the problem!!!)== | + | ==Video Solution 1 (super clear!) by Power Solve== |
+ | https://youtu.be/SG4PRARL0TY | ||
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+ | ==Video Solution 2 by Math-X (First understand the problem!!!)== | ||
https://youtu.be/nKTOYne7E6Y | https://youtu.be/nKTOYne7E6Y | ||
~Math-X | ~Math-X | ||
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==Video Solution 3 by OmegaLearn.org== | ==Video Solution 3 by OmegaLearn.org== |
Revision as of 18:55, 26 January 2024
Contents
[hide]Problem
A chess king is said to attack all the squares one step away from it, horizontally, vertically, or diagonally. For instance, a king on the center square of a x grid attacks all other squares, as shown below. Suppose a white king and a black king are placed on different squares of a x grid so that they do not attack each other. In how many ways can this be done?
(A) (B) (C) (D) (E)
Solution 1
Corners have spots to go and corners so . Sides have spots to go and sides so in total. is the answer.
~andliu766
Solution 2
We see that the center is not a viable spot for either of the kings to be in, as it would attack all nearby squares.
This gives three combinations:
Corner-corner: There are 4 corners, and none of them are touching orthogonally or diagonally, so it's
Corner-edge: For each corner, there are two edges that don't border it,
Edge-edge: The only possible combinations of this that work are top-bottom and left-right edges, so for this type
Multiply by two to account for arrangements of colors to get ~ c_double_sharp
Video Solution 1 (super clear!) by Power Solve
Video Solution 2 by Math-X (First understand the problem!!!)
~Math-X