Difference between revisions of "2024 AMC 10A Problems/Problem 12"
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(Note: I'm aware the formatting is a bit weird, so if someone can help with the formatting, it would be amazing, thanks :)) | (Note: I'm aware the formatting is a bit weird, so if someone can help with the formatting, it would be amazing, thanks :)) | ||
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+ | ==Solution 2== | ||
+ | Compared to the first day <math>(1700)</math>, her scores change by <math>+80</math>, <math>-10</math>, <math>-20</math>, <math>+40</math>, and <math>+0</math>. So, the average is <math>1700 + \frac{80-10-20+40+0}{6} = \boxed{\textbf{(E) }1715}</math>. | ||
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+ | -mathfun2012 | ||
==See Also== | ==See Also== | ||
{{AMC10 box|year=2024|ab=A|num-b=10|num-a=12}} | {{AMC10 box|year=2024|ab=A|num-b=10|num-a=12}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 17:12, 8 November 2024
Contents
[hide]Problem
Zelda played the Adventures of Math game on August 1 and scored points. She continued to play daily over the next days. The bar chart below shows the daily change in her score compared to the day before. (For example, Zelda's score on August 2 was points.) What was Zelda's average score in points over the days?
Solution 1
Going through the table, we see her scores over the six days were: , , , , , and . Taking the average, we get
-i_am_suk_at_math_2
(Note: I'm aware the formatting is a bit weird, so if someone can help with the formatting, it would be amazing, thanks :))
Solution 2
Compared to the first day , her scores change by , , , , and . So, the average is .
-mathfun2012
See Also
2024 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
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