Difference between revisions of "2000 AMC 10 Problems"
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{{AMC10 Problems|year=2000|ab=}} | {{AMC10 Problems|year=2000|ab=}} | ||
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− | <math>\ | + | |
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+ | == Problem 1 == | ||
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+ | In the year <math>2001</math>, the United States will host the International Math Olympiad. Let <math>I, M,</math> and <math>O</math> be distinct positive integers such that the product <math>I\cdot M \cdot O=2001</math>. What is the largest possible sum <math>I+M+O</math>? | ||
+ | |||
+ | <math>\textbf{(A)}\ 23 \qquad\textbf{(B)}\ 55 \qquad\textbf{(C)}\ 99 \qquad\textbf{(D)}\ 111 \qquad\textbf{(E)}\ 671</math> | ||
[[2000 AMC 10 Problems/Problem 1|Solution]] | [[2000 AMC 10 Problems/Problem 1|Solution]] | ||
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<math>2000({2000}^{2000}) =</math> | <math>2000({2000}^{2000}) =</math> | ||
− | <math>\ | + | <math>\textbf{(A)}\ {2000}^{2001} \qquad \textbf{(B)}\ {4000}^{2000} \qquad \textbf{(C)}\ {2000}^{4000} \qquad \textbf{(D)}\ {4,000,000}^{2000} \qquad\textbf{(E)}\ {2000}^{4,000,000}</math> |
[[2000 AMC 10 Problems/Problem 2|Solution]] | [[2000 AMC 10 Problems/Problem 2|Solution]] | ||
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Each day, Jenny ate <math>20\%</math> of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, <math>32</math> remained. How many jellybeans were in the jar originally? | Each day, Jenny ate <math>20\%</math> of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, <math>32</math> remained. How many jellybeans were in the jar originally? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 40 \qquad\textbf{(B)}\ 50 \qquad\textbf{(C)}\ 55 \qquad\textbf{(D)}\ 60 \qquad\textbf{(E)}\ 75</math> |
[[2000 AMC 10 Problems/Problem 3|Solution]] | [[2000 AMC 10 Problems/Problem 3|Solution]] | ||
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Chandra pays an on-line service provider a fixed monthly fee plus an hourly charge for connect time. Her December bill was <math>$12.48</math>, but in January her bill was <math>$17.54</math> because she used twice as much connect time as in December. What is the fixed monthly fee? | Chandra pays an on-line service provider a fixed monthly fee plus an hourly charge for connect time. Her December bill was <math>$12.48</math>, but in January her bill was <math>$17.54</math> because she used twice as much connect time as in December. What is the fixed monthly fee? | ||
− | <math>\ | + | <math>\textbf{(A) } $2.53 \qquad\textbf{(B) } $5.06 \qquad\textbf{(C) } $6.24 \qquad\textbf{(D) } $7.42 \qquad\textbf{(E) } $8.77</math> |
[[2000 AMC 10 Problems/Problem 4|Solution]] | [[2000 AMC 10 Problems/Problem 4|Solution]] | ||
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</asy> | </asy> | ||
− | <math>\ | + | <math>\textbf{(A)}\ 0 \qquad\textbf{(B)}\ 1 \qquad\textbf{(C)}\ 2 \qquad\textbf{(D)}\ 3 \qquad\textbf{(E)}\ 4</math> |
[[2000 AMC 10 Problems/Problem 5|Solution]] | [[2000 AMC 10 Problems/Problem 5|Solution]] | ||
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== Problem 6 == | == Problem 6 == | ||
− | The Fibonacci sequence <math>1, 1, 2, 3, 5, 8, 13, 21, \ldots</math> starts with two <math>1</math>s, and each term afterwards is the sum of its two predecessors. Which one of the ten digits is the last to appear in the units position of a number in the Fibonacci sequence? | + | The Fibonacci sequence <math>1, 1, 2, 3, 5, 8, 13, 21, \ldots</math> starts with two <math>1</math>s, and each term afterwards is the sum of its two predecessors. Which one of the ten digits is the last to appear in the units position of a number in the Fibonacci sequence? |
− | <math>\ | + | <math>\textbf{(A)}\ 0 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 6 \qquad\textbf{(D)}\ 7\qquad\textbf{(E)}\ 9</math> |
[[2000 AMC 10 Problems/Problem 6|Solution]] | [[2000 AMC 10 Problems/Problem 6|Solution]] | ||
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</asy> | </asy> | ||
− | <math>\ | + | <math>\textbf{(A)}\ 3+\frac{\sqrt{3}}{3} \qquad\textbf{(B)}\ 2+\frac{4\sqrt{3}}{3} \qquad\textbf{(C)}\ 2+2\sqrt{2} \qquad\textbf{(D)}\ \frac{3+3\sqrt{5}}{2} \qquad\textbf{(E)}\ 2+\frac{5\sqrt{3}}{3}</math> |
[[2000 AMC 10 Problems/Problem 7|Solution]] | [[2000 AMC 10 Problems/Problem 7|Solution]] | ||
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At Olympic High School, <math>\frac{2}{5}</math> of the freshmen and <math>\frac{4}{5}</math> of the sophomores took the AMC 10. Given that the number of freshmen and sophomore contestants was the same, which of the following must be true? | At Olympic High School, <math>\frac{2}{5}</math> of the freshmen and <math>\frac{4}{5}</math> of the sophomores took the AMC 10. Given that the number of freshmen and sophomore contestants was the same, which of the following must be true? | ||
− | <math>\ | + | <math>\textbf{(A) }</math> There are five times as many sophomores as freshmen. |
− | <math>\ | + | <math>\textbf{(B) }</math> There are twice as many sophomores as freshmen. |
− | <math>\ | + | <math>\textbf{(C) }</math> There are as many freshmen as sophomores. |
− | <math>\ | + | <math>\textbf{(D) }</math> There are twice as many freshmen as sophomores. |
− | <math>\ | + | <math>\textbf{(E) }</math> There are five times as many freshmen as sophomores. |
[[2000 AMC 10 Problems/Problem 8|Solution]] | [[2000 AMC 10 Problems/Problem 8|Solution]] | ||
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If <math>|x-2|=p</math>, where <math>x<2</math>, then <math>x-p=</math> | If <math>|x-2|=p</math>, where <math>x<2</math>, then <math>x-p=</math> | ||
− | <math>\ | + | <math>\textbf{(A)}\ -2 \qquad\textbf{(B)}\ 2 \qquad\textbf{(C)}\ 2-2p \qquad\textbf{(D)}\ 2p-2 \qquad\textbf{(E)}\ |2p-2|</math> |
[[2000 AMC 10 Problems/Problem 9|Solution]] | [[2000 AMC 10 Problems/Problem 9|Solution]] | ||
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The sides of a triangle with positive area have lengths <math>4</math>, <math>6</math>, and <math>x</math>. The sides of a second triangle with positive area have lengths <math>4</math>, <math>6</math>, and <math>y</math>. What is the smallest positive number that is '''not''' a possible value of <math>|x-y|</math>? | The sides of a triangle with positive area have lengths <math>4</math>, <math>6</math>, and <math>x</math>. The sides of a second triangle with positive area have lengths <math>4</math>, <math>6</math>, and <math>y</math>. What is the smallest positive number that is '''not''' a possible value of <math>|x-y|</math>? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 2 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 6 \qquad\textbf{(D)}\ 8 \qquad\textbf{(E)}\ 10</math> |
[[2000 AMC 10 Problems/Problem 10|Solution]] | [[2000 AMC 10 Problems/Problem 10|Solution]] | ||
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Two different prime numbers between <math>4</math> and <math>18</math> are chosen. When their sum is subtracted from their product, which of the following numbers could be obtained? | Two different prime numbers between <math>4</math> and <math>18</math> are chosen. When their sum is subtracted from their product, which of the following numbers could be obtained? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 22 \qquad\textbf{(B)}\ 60 \qquad\textbf{(C)}\ 119 \qquad\textbf{(D)}\ 180 \qquad\textbf{(E)}\ 231</math> |
[[2000 AMC 10 Problems/Problem 11|Solution]] | [[2000 AMC 10 Problems/Problem 11|Solution]] | ||
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− | <math>\ | + | <math>\textbf{(A)}\ 10401 \qquad\textbf{(B)}\ 19801 \qquad\textbf{(C)}\ 20201 \qquad\textbf{(D)}\ 39801 \qquad\textbf{(E)}\ 40801</math> |
[[2000 AMC 10 Problems/Problem 12|Solution]] | [[2000 AMC 10 Problems/Problem 12|Solution]] | ||
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− | <math>\ | + | <math>\textbf{(A)}\ 0 \qquad\textbf{(B)}\ 1 \qquad\textbf{(C)}\ 5!\cdot 4!\cdot 3!\cdot 2!\cdot 1! \qquad\textbf{(D)}\ \frac{15!}{5!\cdot 4!\cdot 3!\cdot 2!\cdot 1!} \qquad\textbf{(E)}\ 15!</math> |
[[2000 AMC 10 Problems/Problem 13|Solution]] | [[2000 AMC 10 Problems/Problem 13|Solution]] | ||
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Mrs. Walter gave an exam in a mathematics class of five students. She entered the scores in random order into a spreadsheet, which recalculated the class average after each score was entered. Mrs. Walter noticed that after each score was entered, the average was always an integer. The scores (listed in ascending order) were <math>71</math>, <math>76</math>, <math>80</math>, <math>82</math>, and <math>91</math>. What was the last score Mrs. Walter entered? | Mrs. Walter gave an exam in a mathematics class of five students. She entered the scores in random order into a spreadsheet, which recalculated the class average after each score was entered. Mrs. Walter noticed that after each score was entered, the average was always an integer. The scores (listed in ascending order) were <math>71</math>, <math>76</math>, <math>80</math>, <math>82</math>, and <math>91</math>. What was the last score Mrs. Walter entered? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 71 \qquad\textbf{(B)}\ 76 \qquad\textbf{(C)}\ 80 \qquad\textbf{(D)}\ 82 \qquad\textbf{(E)}\ 91</math> |
[[2000 AMC 10 Problems/Problem 14|Solution]] | [[2000 AMC 10 Problems/Problem 14|Solution]] | ||
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Two non-zero real numbers, <math>a</math> and <math>b</math>, satisfy <math>ab=a-b</math>. Find a possible value of <math>\frac{a}{b}+\frac{b}{a}-ab</math>. | Two non-zero real numbers, <math>a</math> and <math>b</math>, satisfy <math>ab=a-b</math>. Find a possible value of <math>\frac{a}{b}+\frac{b}{a}-ab</math>. | ||
− | <math>\ | + | <math>\textbf{(A)}\ -2 \qquad\textbf{(B)}\ -\frac{1}{2} \qquad\textbf{(C)}\ \frac{1}{3} \qquad\textbf{(D)}\ \frac{1}{2} \qquad\textbf{(E)}\ 2</math> |
[[2000 AMC 10 Problems/Problem 15|Solution]] | [[2000 AMC 10 Problems/Problem 15|Solution]] | ||
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</asy> | </asy> | ||
− | <math>\ | + | <math>\textbf{(A)}\ \frac{4\sqrt{5}}{3} \qquad\textbf{(B)}\ \frac{5\sqrt{5}}{3} \qquad\textbf{(C)}\ \frac{12\sqrt{5}}{7} \qquad\textbf{(D)}\ 2\sqrt{5} \qquad\textbf{(E)}\ \frac{5\sqrt{65}}{9}</math> |
[[2000 AMC 10 Problems/Problem 16|Solution]] | [[2000 AMC 10 Problems/Problem 16|Solution]] | ||
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== Problem 17 == | == Problem 17 == | ||
− | + | Boris has an incredible coin changing machine. When he puts in a quarter, it returns five nickels; when he puts in a nickel, it returns five pennies; and when he puts in a penny, it returns five quarters. Boris starts with just one penny. Which of the following amounts could Boris have after using the machine repeatedly? | |
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− | <math>\ | + | <math>\textbf{(A) } $3.63 \qquad \textbf{(B) } $5.13 \qquad \textbf{(C) } $6.30 \qquad \textbf{(D) } $7.45 \qquad \textbf{(E) } $9.07</math> |
[[2000 AMC 10 Problems/Problem 17|Solution]] | [[2000 AMC 10 Problems/Problem 17|Solution]] | ||
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Charlyn walks completely around the boundary of a square whose sides are each <math>5</math> km long. From any point on her path she can see exactly <math>1</math> km horizontally in all directions. What is the area of the region consisting of all points Charlyn can see during her walk, expressed in square kilometers and rounded to the nearest whole number? | Charlyn walks completely around the boundary of a square whose sides are each <math>5</math> km long. From any point on her path she can see exactly <math>1</math> km horizontally in all directions. What is the area of the region consisting of all points Charlyn can see during her walk, expressed in square kilometers and rounded to the nearest whole number? | ||
− | <math>\ | + | <math>\textbf{(A) } 24 \qquad\textbf{(B)}\ 27 \qquad\textbf{(C)}\ 39 \qquad\textbf{(D)}\ 40 \qquad\textbf{(E)}\ 42</math> |
[[2000 AMC 10 Problems/Problem 18|Solution]] | [[2000 AMC 10 Problems/Problem 18|Solution]] | ||
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Through a point on the hypotenuse of a right triangle, lines are drawn parallel to the legs of the triangle so that the triangle is divided into a square and two smaller right triangles. The area of one of the two small right triangles is <math>m</math> times the area of the square. The ratio of the area of the other small right triangle to the area of the square is | Through a point on the hypotenuse of a right triangle, lines are drawn parallel to the legs of the triangle so that the triangle is divided into a square and two smaller right triangles. The area of one of the two small right triangles is <math>m</math> times the area of the square. The ratio of the area of the other small right triangle to the area of the square is | ||
− | <math>\ | + | <math>\textbf{(A)}\ \frac{1}{2m+1} \qquad\textbf{(B)}\ m \qquad\textbf{(C)}\ 1-m \qquad\textbf{(D)}\ \frac{1}{4m} \qquad\textbf{(E)}\ \frac{1}{8m^2}</math> |
[[2000 AMC 10 Problems/Problem 19|Solution]] | [[2000 AMC 10 Problems/Problem 19|Solution]] | ||
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Let <math>A</math>, <math>M</math>, and <math>C</math> be nonnegative integers such that <math>A+M+C=10</math>. What is the maximum value of <math>A\cdot M\cdot C+A\cdot M+M\cdot C+C\cdot A</math>? | Let <math>A</math>, <math>M</math>, and <math>C</math> be nonnegative integers such that <math>A+M+C=10</math>. What is the maximum value of <math>A\cdot M\cdot C+A\cdot M+M\cdot C+C\cdot A</math>? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 49 \qquad\textbf{(B)}\ 59 \qquad\textbf{(C)}\ 69 \qquad\textbf{(D)}\ 79 \qquad\textbf{(E)}\ 89</math> |
[[2000 AMC 10 Problems/Problem 20|Solution]] | [[2000 AMC 10 Problems/Problem 20|Solution]] | ||
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<cmath>\textrm{III. Some alligators are not creepy crawlers.}</cmath> | <cmath>\textrm{III. Some alligators are not creepy crawlers.}</cmath> | ||
− | <math>\ | + | <math>\textbf{(A)}\ \text{I only} \qquad\textbf{(B)}\ \text{II only} \qquad\textbf{(C)}\ \text{III only} \qquad\textbf{(D)}\ \text{II and III only} \qquad\textbf{(E)}\ \text{None must be true}</math> |
[[2000 AMC 10 Problems/Problem 21|Solution]] | [[2000 AMC 10 Problems/Problem 21|Solution]] | ||
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One morning each member of Angela's family drank an 8-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family? | One morning each member of Angela's family drank an 8-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 3 \qquad\textbf{(B)}\ 4 \qquad\textbf{(C)}\ 5 \qquad\textbf{(D)}\ 6 \qquad\textbf{(E)}\ 7</math> |
[[2000 AMC 10 Problems/Problem 22|Solution]] | [[2000 AMC 10 Problems/Problem 22|Solution]] | ||
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When the mean, median, and mode of the list <cmath>10,2,5,2,4,2,x</cmath> are arranged in increasing order, they form a non-constant arithmetic progression. What is the sum of all possible real values of <math>x</math>? | When the mean, median, and mode of the list <cmath>10,2,5,2,4,2,x</cmath> are arranged in increasing order, they form a non-constant arithmetic progression. What is the sum of all possible real values of <math>x</math>? | ||
− | <math>\ | + | <math>\textbf{(A)}\ 3 \qquad\textbf{(B)}\ 6 \qquad\textbf{(C)}\ 9 \qquad\textbf{(D)}\ 17 \qquad\textbf{(E)}\ 20</math> |
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+ | |||
+ | |||
[[2000 AMC 10 Problems/Problem 23|Solution]] | [[2000 AMC 10 Problems/Problem 23|Solution]] | ||
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Let <math>f</math> be a function for which <math>f\left(\frac{x}{3}\right)=x^2+x+1</math>. Find the sum of all values of <math>z</math> for which <math>f(3z)=7</math>. | Let <math>f</math> be a function for which <math>f\left(\frac{x}{3}\right)=x^2+x+1</math>. Find the sum of all values of <math>z</math> for which <math>f(3z)=7</math>. | ||
− | <math>\ | + | <math>\textbf{(A)}\ -\frac{1}{3} \qquad\textbf{(B)}\ -\frac{1}{9} \qquad\textbf{(C)}\ 0 \qquad\textbf{(D)}\ \frac{5}{9} \qquad\textbf{(E)}\ \frac{5}{3}</math> |
[[2000 AMC 10 Problems/Problem 24|Solution]] | [[2000 AMC 10 Problems/Problem 24|Solution]] | ||
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In year <math>N</math>, the <math>300^\text{th}</math> day of the year is a Tuesday. In year <math>N+1</math>, the <math>200^\text{th}</math> day is also a Tuesday. On what day of the week did the <math>100^\text{th}</math> day of year <math>N-1</math> occur? | In year <math>N</math>, the <math>300^\text{th}</math> day of the year is a Tuesday. In year <math>N+1</math>, the <math>200^\text{th}</math> day is also a Tuesday. On what day of the week did the <math>100^\text{th}</math> day of year <math>N-1</math> occur? | ||
− | <math>\ | + | <math>\textbf{(A)}\ \text{Thursday} \qquad\textbf{(B)}\ \text{Friday} \qquad\textbf{(C)}\ \text{Saturday} \qquad\textbf{(D)}\ \text{Sunday} \qquad\textbf{(E)}\ \text{Monday}</math> |
[[2000 AMC 10 Problems/Problem 25|Solution]] | [[2000 AMC 10 Problems/Problem 25|Solution]] | ||
== See also == | == See also == | ||
− | {{AMC10 box|year=2000|before= | + | {{AMC10 box|year=2000|before=This was the first<br />AMC 10|after=[[2001 AMC 10 Problems|2001 AMC 10]]}} |
* [[AMC 10]] | * [[AMC 10]] | ||
* [[AMC 10 Problems and Solutions]] | * [[AMC 10 Problems and Solutions]] | ||
* [[Mathematics competition resources]] | * [[Mathematics competition resources]] | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 00:12, 10 November 2024
2000 AMC 10 (Answer Key) Printable versions: • AoPS Resources • PDF | ||
Instructions
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1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 |
Contents
[hide]- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 See also
Problem 1
In the year , the United States will host the International Math Olympiad. Let and be distinct positive integers such that the product . What is the largest possible sum ?
Problem 2
Problem 3
Each day, Jenny ate of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, remained. How many jellybeans were in the jar originally?
Problem 4
Chandra pays an on-line service provider a fixed monthly fee plus an hourly charge for connect time. Her December bill was , but in January her bill was because she used twice as much connect time as in December. What is the fixed monthly fee?
Problem 5
Points and are the midpoints of sides and of . As moves along a line that is parallel to side , how many of the four quantities listed below change?
(a) the length of the segment
(b) the perimeter of
(c) the area of
(d) the area of trapezoid
Problem 6
The Fibonacci sequence starts with two s, and each term afterwards is the sum of its two predecessors. Which one of the ten digits is the last to appear in the units position of a number in the Fibonacci sequence?
Problem 7
In rectangle , , is on , and and trisect . What is the perimeter of ?
Problem 8
At Olympic High School, of the freshmen and of the sophomores took the AMC 10. Given that the number of freshmen and sophomore contestants was the same, which of the following must be true?
There are five times as many sophomores as freshmen.
There are twice as many sophomores as freshmen.
There are as many freshmen as sophomores.
There are twice as many freshmen as sophomores.
There are five times as many freshmen as sophomores.
Problem 9
If , where , then
Problem 10
The sides of a triangle with positive area have lengths , , and . The sides of a second triangle with positive area have lengths , , and . What is the smallest positive number that is not a possible value of ?
Problem 11
Two different prime numbers between and are chosen. When their sum is subtracted from their product, which of the following numbers could be obtained?
Problem 12
Figures , , , and consist of , , , and nonoverlapping unit squares, respectively. If the pattern were continued, how many nonoverlapping unit squares would there be in figure 100?
Problem 13
There are 5 yellow pegs, 4 red pegs, 3 green pegs, 2 blue pegs, and 1 orange peg to be placed on a triangular peg board. In how many ways can the pegs be placed so that no (horizontal) row or (vertical) column contains two pegs of the same color?
Problem 14
Mrs. Walter gave an exam in a mathematics class of five students. She entered the scores in random order into a spreadsheet, which recalculated the class average after each score was entered. Mrs. Walter noticed that after each score was entered, the average was always an integer. The scores (listed in ascending order) were , , , , and . What was the last score Mrs. Walter entered?
Problem 15
Two non-zero real numbers, and , satisfy . Find a possible value of .
Problem 16
The diagram shows lattice points, each one unit from its nearest neighbors. Segment meets segment at . Find the length of segment .
Problem 17
Boris has an incredible coin changing machine. When he puts in a quarter, it returns five nickels; when he puts in a nickel, it returns five pennies; and when he puts in a penny, it returns five quarters. Boris starts with just one penny. Which of the following amounts could Boris have after using the machine repeatedly?
Problem 18
Charlyn walks completely around the boundary of a square whose sides are each km long. From any point on her path she can see exactly km horizontally in all directions. What is the area of the region consisting of all points Charlyn can see during her walk, expressed in square kilometers and rounded to the nearest whole number?
Problem 19
Through a point on the hypotenuse of a right triangle, lines are drawn parallel to the legs of the triangle so that the triangle is divided into a square and two smaller right triangles. The area of one of the two small right triangles is times the area of the square. The ratio of the area of the other small right triangle to the area of the square is
Problem 20
Let , , and be nonnegative integers such that . What is the maximum value of ?
Problem 21
If all alligators are ferocious creatures and some creepy crawlers are alligators, which statement(s) must be true?
Problem 22
One morning each member of Angela's family drank an 8-ounce mixture of coffee with milk. The amounts of coffee and milk varied from cup to cup, but were never zero. Angela drank a quarter of the total amount of milk and a sixth of the total amount of coffee. How many people are in the family?
Problem 23
When the mean, median, and mode of the list are arranged in increasing order, they form a non-constant arithmetic progression. What is the sum of all possible real values of ?
Problem 24
Let be a function for which . Find the sum of all values of for which .
Problem 25
In year , the day of the year is a Tuesday. In year , the day is also a Tuesday. On what day of the week did the day of year occur?
See also
2000 AMC 10 (Problems • Answer Key • Resources) | ||
Preceded by This was the first AMC 10 |
Followed by 2001 AMC 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.