Difference between revisions of "2024 AMC 8 Problems/Problem 17"
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==Solution 1== | ==Solution 1== | ||
− | If you place a king in any of the <math>4</math> corners, | + | If you place a king in any of the <math>4</math> corners, the other king will have <math>5</math> spots to go and there are <math>4</math> corners, so <math>5 \times 4=20</math>. |
− | If you place a king in any of the <math> | + | If you place a king in any of the <math>4</math> edges, the other king will have <math>3</math> spots to go and there are <math>4</math> edges so <math>3 \times 4=12</math>. |
− | That gives us <math>20+12=32</math> spots to go into | + | That gives us <math>20+12=32</math> spots for the other king to go into in total. |
So <math>\boxed{\textbf{(E)} 32}</math> is the answer. | So <math>\boxed{\textbf{(E)} 32}</math> is the answer. | ||
~andliu766, captaindiamond868 (minor edits) | ~andliu766, captaindiamond868 (minor edits) | ||
+ | ~AliceDubbleYou | ||
==Solution 2== | ==Solution 2== | ||
Line 52: | Line 53: | ||
~Math-X | ~Math-X | ||
+ | |||
+ | ==Video Solution (A Clever Explanation You’ll Get Instantly)== | ||
+ | https://youtu.be/5ZIFnqymdDQ?si=_SHs3ZXS1ZKF4-v2&t=2381 | ||
+ | ~hsnacademy | ||
==Video Solution 2 (super clear!) by Power Solve== | ==Video Solution 2 (super clear!) by Power Solve== | ||
Line 71: | Line 76: | ||
==Video Solution by Interstigation== | ==Video Solution by Interstigation== | ||
https://youtu.be/ktzijuZtDas&t=1922 | https://youtu.be/ktzijuZtDas&t=1922 | ||
+ | |||
+ | ==Video Solution by Dr. David== | ||
+ | https://youtu.be/vO1rcJZzIrQ | ||
+ | |||
+ | ==Video Solution by WhyMath== | ||
+ | https://youtu.be/psiAz9Owyzk | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2024|num-b=16|num-a=18}} | {{AMC8 box|year=2024|num-b=16|num-a=18}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 06:47, 15 November 2024
Contents
[hide]- 1 Problem
- 2 Solution 1
- 3 Solution 2
- 4 Video Solution 1 by Math-X (First understand the problem!!!)
- 5 Video Solution (A Clever Explanation You’ll Get Instantly)
- 6 Video Solution 2 (super clear!) by Power Solve
- 7 Video Solution 3 by OmegaLearn.org
- 8 Video Solution 4 by SpreadTheMathLove
- 9 Video Solution by NiuniuMaths (Easy to understand!)
- 10 Video Solution by CosineMethod [🔥Fast and Easy🔥]
- 11 Video Solution by Interstigation
- 12 Video Solution by Dr. David
- 13 Video Solution by WhyMath
- 14 See Also
Problem
A chess king is said to attack all the squares one step away from it, horizontally, vertically, or diagonally. For instance, a king on the center square of a x grid attacks all other squares, as shown below. Suppose a white king and a black king are placed on different squares of a x grid so that they do not attack each other (in other words, not right next to each other). In how many ways can this be done?
~Diagram by Andrei.martynau
Solution 1
If you place a king in any of the corners, the other king will have spots to go and there are corners, so . If you place a king in any of the edges, the other king will have spots to go and there are edges so . That gives us spots for the other king to go into in total. So is the answer. ~andliu766, captaindiamond868 (minor edits) ~AliceDubbleYou
Solution 2
We see that the center is not a viable spot for either of the kings to be in, as it would attack all nearby squares.
This gives three combinations:
Corner-corner: There are 4 corners, and none of them are touching orthogonally or diagonally, so it's
Corner-edge: For each corner, there are two edges that don't border it,
Edge-edge: The only possible combinations of this that work are top-bottom and left-right edges, so for this type
Multiply by two to account for arrangements of colors to get ~ c_double_sharp
Video Solution 1 by Math-X (First understand the problem!!!)
https://youtu.be/BaE00H2SHQM?si=Q2e8OfkuzKZXmoau&t=4624
~Math-X
Video Solution (A Clever Explanation You’ll Get Instantly)
https://youtu.be/5ZIFnqymdDQ?si=_SHs3ZXS1ZKF4-v2&t=2381 ~hsnacademy
Video Solution 2 (super clear!) by Power Solve
Video Solution 3 by OmegaLearn.org
Video Solution 4 by SpreadTheMathLove
https://www.youtube.com/watch?v=Svibu3nKB7E
Video Solution by NiuniuMaths (Easy to understand!)
https://www.youtube.com/watch?v=V-xN8Njd_Lc
~NiuniuMaths
Video Solution by CosineMethod [🔥Fast and Easy🔥]
https://www.youtube.com/watch?v=quWFZIahQCg
Video Solution by Interstigation
https://youtu.be/ktzijuZtDas&t=1922
Video Solution by Dr. David
Video Solution by WhyMath
See Also
2024 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.