Difference between revisions of "2024 AMC 8 Problems/Problem 21"

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-ILoveMath31415926535
 
-ILoveMath31415926535
  
==Solution 3==
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==Solution 3 (Simple and easy to make sense of)==
  
The ratio of <math>g</math> (green) to <math>y</math> (yellow) frogs is <math>3:1</math>. When <math>3</math> green frogs move to the sunny side and <math>5</math> yellow frogs move to the shady side, you can tell that the ratio <math>g + 2:y - 2</math> is <math>4:1</math>.  
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The ratio of <math>g</math> (green) to <math>y</math> (yellow) frogs is <math>3:1</math>. When <math>3</math> green frogs move to the sunny side and <math>5</math> yellow frogs move to the shady side, the ratio becomes <math>g + 2:y - 2</math> which is <math>4:1</math>.  
  
So earlier, <math>\frac{3}{4}</math>, or <math>\frac{15}{20}</math>, of the total frogs were green. Now, <math>\frac{4}{5}</math>, or <math>\frac{16}{20}</math>, of the total frogs are green. When the green side gained <math>2</math> frogs and the yellow side lost <math>2</math> frogs, the green side gained <math>\frac{1}{20}</math> of the total amount of frogs. So <math>2</math> = <math>\frac{1}{20}</math><math>a</math>, where <math>a</math> is the total number of frogs. Solving for <math>a</math> we get <math>a</math> = <math>40</math>.
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So earlier, <math>\frac{3}{4}</math>, or <math>\frac{15}{20}</math>, of the total frogs were green. Now, <math>\frac{4}{5}</math>, or <math>\frac{16}{20}</math>, of the total frogs are green. When the <math>2</math> frogs transferred from the yellow side to the green, the green side gained <math>\frac{1}{20}</math> of the total amount of frogs. So, <math>2</math> = <math>\frac{1}{20}</math><math>a</math>, where <math>a</math> is the total number of frogs. Solving for <math>a</math> we get <math>a</math> = <math>40</math>.
  
 
If the ratio <math>4: 1</math> has a total of <math>40</math>, then we can multiply each of them by <math>\frac{40}{(4 + 1)}</math>, or <math>8</math>, and find that there are <math>32</math> green frogs and <math>8</math> yellow frogs. Therefore, the difference between the green and yellow frogs is <math>\boxed{\textbf{(E) }24}</math>
 
If the ratio <math>4: 1</math> has a total of <math>40</math>, then we can multiply each of them by <math>\frac{40}{(4 + 1)}</math>, or <math>8</math>, and find that there are <math>32</math> green frogs and <math>8</math> yellow frogs. Therefore, the difference between the green and yellow frogs is <math>\boxed{\textbf{(E) }24}</math>
  
==Video Solution (A Clever Explanation You’ll Get Instantly)==
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~mihikamishra
https://youtu.be/5ZIFnqymdDQ?si=l3dF11eyLXoyI9Ow&t=3107
 
 
 
~hsnacademy
 
  
 
==Video Solution 1 by Math-X (First fully understand the problem!!!)==
 
==Video Solution 1 by Math-X (First fully understand the problem!!!)==
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~Math-X
 
~Math-X
 +
 +
==Video Solution (A Clever Explanation You’ll Get Instantly)==
 +
https://youtu.be/5ZIFnqymdDQ?si=l3dF11eyLXoyI9Ow&t=3107
 +
~hsnacademy
  
 
https://youtu.be/H7d8c_YnvqE
 
https://youtu.be/H7d8c_YnvqE
 
Please like and subscribe!
 
  
 
==Video Solution by Power Solve (crystal clear)==
 
==Video Solution by Power Solve (crystal clear)==
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https://www.youtube.com/watch?v=3SUTUr1My7c&t=1s
 
https://www.youtube.com/watch?v=3SUTUr1My7c&t=1s
 +
 
==Video Solution by Interstigation==
 
==Video Solution by Interstigation==
 
https://youtu.be/ktzijuZtDas&t=2562
 
https://youtu.be/ktzijuZtDas&t=2562
 +
 +
==Video Solution by Dr. David==
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https://youtu.be/d6Xtre2bwro
 +
 +
==Video Solution by WhyMath==
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https://youtu.be/GtyynnIF1ZM
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2024|num-b=20|num-a=22}}
 
{{AMC8 box|year=2024|num-b=20|num-a=22}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 06:52, 15 November 2024

Problem

A group of frogs (called an army) is living in a tree. A frog turns green when in the shade and turns yellow when in the sun. Initially, the ratio of green to yellow frogs was $3 : 1$. Then $3$ green frogs moved to the sunny side and $5$ yellow frogs moved to the shady side. Now the ratio is $4 : 1$. What is the difference between the number of green frogs and the number of yellow frogs now?

$\textbf{(A) } 10\qquad\textbf{(B) } 12\qquad\textbf{(C) } 16\qquad\textbf{(D) } 20\qquad\textbf{(E) } 24$


Solution 1

Let the initial number of green frogs be $g$ and the initial number of yellow frogs be $y$. Since the ratio of the number of green frogs to yellow frogs is initially $3 : 1$, $g = 3y$. Now, $3$ green frogs move to the sunny side and $5$ yellow frogs move to the shade side, thus the new number of green frogs is $g + 2$ and the new number of yellow frogs is $y - 2$. We are given that $\frac{g + 2}{y - 2} = \frac{4}{1}$, so $g + 2 = 4y - 8$, since $g = 3y$, we have $3y + 2 = 4y - 8$, so $y = 10$ and $g = 30$. Thus the answer is $(g + 2) - (y - 2) = 32 - 8 = 24$

-anonchalantdreadhead

Solution 2

Since the original ratio is $3:1$ and the new ratio is $4:1$, the number of frogs must be a multiple of $12$, the only solutions left are $(B)$ and $(E)$.

Let's start with $12$ frogs:

We must have $9$ frogs in the shade and $3$ frogs in the sun. After the change, there would be $11$ frogs in the shade and $1$ frog in the sun, which is not a $4:1$ ratio.

Therefore the answer is: $\boxed{(E) \hspace{1 mm} 24}$.

-ILoveMath31415926535

Solution 3 (Simple and easy to make sense of)

The ratio of $g$ (green) to $y$ (yellow) frogs is $3:1$. When $3$ green frogs move to the sunny side and $5$ yellow frogs move to the shady side, the ratio becomes $g + 2:y - 2$ which is $4:1$.

So earlier, $\frac{3}{4}$, or $\frac{15}{20}$, of the total frogs were green. Now, $\frac{4}{5}$, or $\frac{16}{20}$, of the total frogs are green. When the $2$ frogs transferred from the yellow side to the green, the green side gained $\frac{1}{20}$ of the total amount of frogs. So, $2$ = $\frac{1}{20}$$a$, where $a$ is the total number of frogs. Solving for $a$ we get $a$ = $40$.

If the ratio $4: 1$ has a total of $40$, then we can multiply each of them by $\frac{40}{(4 + 1)}$, or $8$, and find that there are $32$ green frogs and $8$ yellow frogs. Therefore, the difference between the green and yellow frogs is $\boxed{\textbf{(E) }24}$

~mihikamishra

Video Solution 1 by Math-X (First fully understand the problem!!!)

https://youtu.be/BaE00H2SHQM?si=yTyYiS2S75HoSfmI&t=6313

~Math-X

Video Solution (A Clever Explanation You’ll Get Instantly)

https://youtu.be/5ZIFnqymdDQ?si=l3dF11eyLXoyI9Ow&t=3107 ~hsnacademy

https://youtu.be/H7d8c_YnvqE

Video Solution by Power Solve (crystal clear)

https://www.youtube.com/watch?v=HodW9H55ZsE

Video Solution 2 by OmegaLearn.org

https://youtu.be/Ah1WTdk8nuA

Video Solution 3 by SpreadTheMathLove

https://www.youtube.com/watch?v=3ItvjukLqK0

Video Solution by NiuniuMaths (Easy to understand!)

https://www.youtube.com/watch?v=looAMewBACY

~NiuniuMaths

Video Solution by CosineMethod [🔥Fast and Easy🔥]

https://www.youtube.com/watch?v=3SUTUr1My7c&t=1s

Video Solution by Interstigation

https://youtu.be/ktzijuZtDas&t=2562

Video Solution by Dr. David

https://youtu.be/d6Xtre2bwro

Video Solution by WhyMath

https://youtu.be/GtyynnIF1ZM

See Also

2024 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 20
Followed by
Problem 22
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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