Difference between revisions of "2023 AMC 8 Problems/Problem 10"

 
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* The porcupine ate <math>\frac13\cdot\frac12 = \frac16</math> of the pie. After that, <math>\frac12 - \frac16 = \boxed{\textbf{(D)}\ \frac{1}{3}}</math> of the pie was left behind.
 
* The porcupine ate <math>\frac13\cdot\frac12 = \frac16</math> of the pie. After that, <math>\frac12 - \frac16 = \boxed{\textbf{(D)}\ \frac{1}{3}}</math> of the pie was left behind.
  
Alternatively, we can condense the solution above into the following equation: <cmath>\left(1-\frac14\right)\left(1-\frac13\right)\left(1-\frac13\right) = \frac34\cdot\frac23\cdot\frac23 = \frac13.</cmath>
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More simply, we can condense the solution above into the following equation: <cmath>\left(1-\frac14\right)\left(1-\frac13\right)\left(1-\frac13\right) = \frac34\cdot\frac23\cdot\frac23 = \frac13.</cmath>
  
 
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM
 
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM
  
==(Creative Thinking) Video Solution==
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==Remark==
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This problem is a great example of the implementation of <b>remaining portions</b>. This concept, in short, refers to the method of finding out what remains of a whole when part of it is taken. If you look closely at our solution, we can see that the denominator is the same when we said Harold ate <math>\frac14</math> of the pie and we got <math>\frac34</math> of the pie left. We can also see the numerator is just the denominator minus the old denominator.
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~Nivaar
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==Video Solution by Math-X (Let's first Understand the question)==
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https://youtu.be/Ku_c1YHnLt0?si=N3jXnFg5Zy3GCgrB&t=1500 ~Math-X
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 +
==Video Solution (HOW TO THINK CREATIVELY!!!) ==
 
https://youtu.be/WKcH7Cyeipo
 
https://youtu.be/WKcH7Cyeipo
 
 
~Education the Study of everything
 
~Education the Study of everything
  
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==Video Solution by Interstigation==
 
==Video Solution by Interstigation==
https://youtu.be/1bA7fD7Lg54?t=646
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https://youtu.be/DBqko2xATxs&t=859
  
 
==Video Solution by harungurcan==
 
==Video Solution by harungurcan==
 
https://www.youtube.com/watch?v=oIGy79w1H8o&t=246s
 
https://www.youtube.com/watch?v=oIGy79w1H8o&t=246s
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 +
==Video Solution by SpreradTheMathLove==
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https://www.youtube.com/watch?v=TAa6jarbATE
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==Video Solution by Dr. David==
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https://youtu.be/BCEMLHWsw2o
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==Video Solution by WhyMath==
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https://youtu.be/EYCq78Fg1RY
  
 
==See Also==  
 
==See Also==  
 
{{AMC8 box|year=2023|num-b=9|num-a=11}}
 
{{AMC8 box|year=2023|num-b=9|num-a=11}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 10:09, 18 November 2024

Problem

Harold made a plum pie to take on a picnic. He was able to eat only $\frac{1}{4}$ of the pie, and he left the rest for his friends. A moose came by and ate $\frac{1}{3}$ of what Harold left behind. After that, a porcupine ate $\frac{1}{3}$ of what the moose left behind. How much of the original pie still remained after the porcupine left?

$\textbf{(A)}\ \frac{1}{12} \qquad \textbf{(B)}\ \frac{1}{6} \qquad \textbf{(C)}\ \frac{1}{4} \qquad \textbf{(D)}\ \frac{1}{3} \qquad \textbf{(E)}\ \frac{5}{12}$

Solution

Note that:

  • Harold ate $\frac14$ of the pie. After that, $1-\frac14=\frac34$ of the pie was left behind.
  • The moose ate $\frac13\cdot\frac34 = \frac14$ of the pie. After that, $\frac34 - \frac14 = \frac12$ of the pie was left behind.
  • The porcupine ate $\frac13\cdot\frac12 = \frac16$ of the pie. After that, $\frac12 - \frac16 = \boxed{\textbf{(D)}\ \frac{1}{3}}$ of the pie was left behind.

More simply, we can condense the solution above into the following equation: \[\left(1-\frac14\right)\left(1-\frac13\right)\left(1-\frac13\right) = \frac34\cdot\frac23\cdot\frac23 = \frac13.\]

~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, MRENTHUSIASM

Remark

This problem is a great example of the implementation of remaining portions. This concept, in short, refers to the method of finding out what remains of a whole when part of it is taken. If you look closely at our solution, we can see that the denominator is the same when we said Harold ate $\frac14$ of the pie and we got $\frac34$ of the pie left. We can also see the numerator is just the denominator minus the old denominator.

~Nivaar

Video Solution by Math-X (Let's first Understand the question)

https://youtu.be/Ku_c1YHnLt0?si=N3jXnFg5Zy3GCgrB&t=1500 ~Math-X

Video Solution (HOW TO THINK CREATIVELY!!!)

https://youtu.be/WKcH7Cyeipo ~Education the Study of everything

Video Solution by Magic Square

https://youtu.be/-N46BeEKaCQ?t=4814

Video Solution by Interstigation

https://youtu.be/DBqko2xATxs&t=859

Video Solution by harungurcan

https://www.youtube.com/watch?v=oIGy79w1H8o&t=246s

Video Solution by SpreradTheMathLove

https://www.youtube.com/watch?v=TAa6jarbATE

Video Solution by Dr. David

https://youtu.be/BCEMLHWsw2o

Video Solution by WhyMath

https://youtu.be/EYCq78Fg1RY

See Also

2023 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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