Difference between revisions of "User:Herefishyfishy1"
(New page: <math>i^n=cis(\frac{\pi n}{2})</math> <math>\forall a,b,c,n\in \mathbb{N}, n>2\Longrightarrow a^n+b^n\not=c^n</math>) |
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Revision as of 10:47, 13 July 2008
(New page: <math>i^n=cis(\frac{\pi n}{2})</math> <math>\forall a,b,c,n\in \mathbb{N}, n>2\Longrightarrow a^n+b^n\not=c^n</math>) |
(No difference)
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