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Difference between revisions of "1987 AJHSME Problems/Problem 6"

(New page: ==Problem== The smallest product one could obtain by multiplying two numbers in the set <math>\{ -7,-5,-1,1,3 \}</math> is <math>\text{(A)}\ -35 \qquad \text{(B)}\ -21 \qquad \text{(C)}\...)
(No difference)

Revision as of 19:08, 14 February 2009

Problem

The smallest product one could obtain by multiplying two numbers in the set $\{ -7,-5,-1,1,3 \}$ is

$\text{(A)}\ -35 \qquad \text{(B)}\ -21 \qquad \text{(C)}\ -15 \qquad \text{(D)}\ -1 \qquad \text{(E)}\ 3$

Solution

To get the smallest possible product, we want to multiply the smallest negative number by the largest positive number. These are $-7$ and $3$, respectively, and their product is $-21$, which is $\boxed{\text{B}}$

See Also

1987 AJHSME Problems

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