Difference between revisions of "2009 AMC 10A Problems/Problem 21"
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& = \frac{3 - 2\sqrt 2}1 \ | & = \frac{3 - 2\sqrt 2}1 \ | ||
& = \boxed{3 - 2\sqrt 2} | & = \boxed{3 - 2\sqrt 2} | ||
+ | |||
+ | |||
+ | But the answer is C. | ||
\end{align*} | \end{align*} | ||
</cmath> | </cmath> |
Revision as of 00:41, 25 February 2009
Problem
Many Gothic cathedrals have windows with portions containing a ring of congruent circles that are circumscribed by a larger circle, In the figure shown, the number of smaller circles is four. What is the ratio of the sum of the areas of the four smaller circles to the area of the larger circle?
Solution
Draw some of the radii of the small circles as in the picture below.
It is now obvious that the radius of the large circle can be expressed using the radius of the small circles as . Then the area of the large circle is . The area of four small circles is . Hence their ratio is:
\begin{align*} \frac SL & = \frac{4\pi r^2}{4\pi r^2 (3+2\sqrt 2)} \\ & = \frac 1{3+2\sqrt 2} \\ & = \frac 1{3+2\sqrt 2} \cdot \frac{3-2\sqrt 2}{3 - 2\sqrt 2} \\ & = \frac{3 - 2\sqrt 2}{3^2 - (2\sqrt 2)^2} \\ & = \frac{3 - 2\sqrt 2}1 \\ & = \boxed{3 - 2\sqrt 2} But the answer is C. \end{align*} (Error compiling LaTeX. Unknown error_msg)
See Also
2009 AMC 10A (Problems • Answer Key • Resources) | ||
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All AMC 10 Problems and Solutions |