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Difference between revisions of "1961 AHSME Problems/Problem 8"

(Created page with 'Let the two base angles of a triangle be ''A'' and ''B'', with ''B'' larger than ''A''. The altitude to the base divides the vertex angle ''C'' into two parts, <math>C_1 and C_2<…')
(No difference)

Revision as of 16:09, 1 October 2009

Let the two base angles of a triangle be A and B, with B larger than A. The altitude to the base divides the vertex angle C into two parts, $C_1 and C_2$, with $C_2$ adjacent to side a. Then:

(A) $C_1+C_2=A+B$

(B) $C_1-C_2=B-A$

(C) $C_1-C_2=A-B$

(D) $C_1+C_2=B-A$

(E) $C_1-C_2=A+B$

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