Difference between revisions of "Steiner's Theorem"

Revision as of 09:03, 3 July 2011

Steiner's Theorem states that in a trapezoid $ABCD$ with $AB\parallel CD$ and $AD\nparallel BC$ , we have that the midpoint of $AB$ and $CD$ , the intersection of diagonals $AC$ and $BD$ , and the intersection of the sides $AD$ and $BC$ are [[collinear].

Proof

Let $E$ be the intersection of $AD$ and $BC$ , $F$ be the midpiont of $AB$ , $G$ be the midpoint of $CD$ , and $H$ be the intersection of $AC$ and $BD$ . We now claim that $\triangle EAF \sim \triangle EDG$ . First note that, since $\angle DEC=\angle AEB$ and $\angle EAB=\angle EDC$ [this is because $AB\parallel CD$ ], we have that $\triangle EDC\sim \triangle EAB$ . Then $\frac{EA}{AB}=\frac{ED}{DC}$ , and $\frac{AF}{AB}=\frac{DG}{DC}=\frac{1}{2}$ , so $\frac{EA}{AF}=\frac{ED}{DG}$ . We earlier stated that $\angle EDC=\angle EAB$ , so we have that $\triangle EAF \sim \triangle EDG$ from SAS similarity. We have that $E$ , $A$ , and $D$ are collinear, and since $F$ and $G$ are on the same side of line $AD$ , we [will continue later]

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Difference between revisions of "Steiner's Theorem"

Revision as of 09:03, 3 July 2011

Proof

See also