Difference between revisions of "1995 AJHSME Problems/Problem 4"

Revision as of 19:23, 1 August 2011

Problem

A teacher tells the class,

"Think of a number, add 1 to it, and double the result. Give the answer to your partner. Partner, subtract 1 from the number you are given and double the result to get your answer."

Ben thinks of $6$ , and gives his answer to Sue. What should Sue's answer be?

$\text{(A)}\ 18 \qquad \text{(B)}\ 24 \qquad \text{(C)}\ 26 \qquad \text{(D)}\ 27 \qquad \text{(E)}\ 30$

Solution

Ben adds $1$ to $6$ , getting $1 + 6 = 7$ . Then Ben doubles it, to get $7\cdot 2 = 14$ . He gives this number to Sue. Then Sue subtracts $1$ from the number, to get $14 - 1 = 13$ . Finally, Sue doubles the result to get $13\cdot 2 = 26$ , and the answer is $\boxed{C}$ .

1995 AJHSME (Problems • Answer Key • Resources)
Preceded by Problem 3	Followed by Problem 5
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Difference between revisions of "1995 AJHSME Problems/Problem 4"

Revision as of 19:23, 1 August 2011

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Solution

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