Difference between revisions of "Induction"
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===Introductory=== | ===Introductory=== | ||
− | Prove that <math>1^3+2^3+...+n^3=(1+2+...+n)^2</math>. | + | * Prove that <math>1^3+2^3+...+n^3=(1+2+...+n)^2</math>. |
===Intermediate=== | ===Intermediate=== |
Revision as of 11:34, 22 September 2011
Induction is a method of proof which the desired result is first shown to hold for a certain value (the Base Case); it is then shown that if the desired result holds for a certain value, it then holds for another, closely related value. Typically, this means proving first that the result holds for (in the Base Case), and then proving that having the result hold for implies that the result holds for . In this way, we can shown that the result holds for all positive integers; we will have showed that it works for , and that implies that it works for , which in turn means it works for , and so on.
Other, odder inductions are possible. If a problem asks you to prove something for all integers greater than 3, you can use as your base case instead. You might have to induct over the even positive integers numbers instead of all of them; in this case, you would take as your base case, and show that if gives the desired result, so does . If you wish, you can similarly induct over the powers of 2.
Contents
[hide]Example
Here is a simple example of how induction works. Below is a proof (by induction, of course) that the th triangular number is indeed equal to (the th triangular number is defined as ; imagine an equilateral triangle composed of evenly spaced dots).
Base Case: . .
Induction Step: Suppose the conclusion is valid for . That is, suppose we have . Adding to both sides, we get , so we can see that the conclusion holding for implies that it holds for , and our induction is complete.
Uses
Induction can be useful in almost any branch of mathematics. Often, problems in number theory and combinatorics are especially susceptible to induction solutions, but that's not to say that there aren't any problems in other areas, such as Inequalities, that can be solved with induction.
Induction is also useful in any level of mathematics that has an emphasis on proof. Induction problems can be found anywhere from the Power Round of the ARML up through the USAMTS all the way up to the USAMO and IMO. A good example of an upper-level problem that can be solved with induction is USAMO 2006/5.
Problems
Introductory
- Prove that .
Intermediate
- Prove that for all integers . (The Art and Craft of Problem Solving)
- For any set whose elements are positive integers, define to be the square of the product of the elements of . For example, if , then . For any positive integer , consider all nonempty subsets of that do not contain two consecutive integers. Prove that the sum of all the f(S)’s of these subsets is .
Olympiad
- Prove Fermat's Little Theorem.
- A function defined on the positive integers satisfies and . Calculate . (United Kingdom 1996/2)