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Difference between revisions of "2004 AMC 8 Problems/Problem 3"

(Created page with "== Problem == Twelve friends met for dinner at Oscar's Overstuffed Oyster House, and each ordered one meal. The portions were so large, there was enough food for <math>18</math> ...")
(No difference)

Revision as of 23:22, 11 March 2012

Problem

Twelve friends met for dinner at Oscar's Overstuffed Oyster House, and each ordered one meal. The portions were so large, there was enough food for $18$ people. If they shared, how many meals should they have ordered to have just enough food for the $12$ of them?

$\textbf{(A)}\ 8\qquad\textbf{(B)}\ 9\qquad\textbf{(C)}\ 10\qquad\textbf{(D)}\ 15\qquad\textbf{(E)}\ 18$

Solution

Set up the proportion $\frac{12\text{meals}}{18\text{people}}=\frac{x\text{meals}}{12\text{people}}$. Solving for $x$ gives us $x=8 \Rightarrow \boxed{\textbf{(A)}\ 8}$

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