Difference between revisions of "KGS math club/solution 11 24"
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Latest revision as of 13:57, 4 June 2013
This is one possible solution.
There are infinitely many solutions, falling into two classes.
One class contains one solution, with 8n+4 pieces, for each positive integer n. The solution above is for the case n=1.
The other class contains many solutions, each with (p+1)(4n+2) pieces, for each pair of positive integers n,p.