Difference between revisions of "1993 AHSME Problems/Problem 9"
(Created page with "== Problem == Country <math>A</math> has <math>c\%</math> of the world's population and <math>d\%</math> of the worlds wealth. Country <math>B</math> has <math>e\%</math> of the...") |
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== Solution == | == Solution == | ||
+ | If country <math>A</math> has <math>\frac{d}{100}</math> of the wealth in the world and <math>c</math> people that means that each person has | ||
+ | <math>\frac{d}{100c}</math> of all the wealth in the world. Using a similar argument for Country <math>B</math> we have that each person has <math>\frac{f}{100e}</math> of the wealth In the world. Evaluating the desired fraction gives us <math>\frac{de}{cf}</math> | ||
<math>\fbox{D}</math> | <math>\fbox{D}</math> | ||
Revision as of 15:42, 8 August 2016
Problem
Country has
of the world's population and
of the worlds wealth. Country
has
of the world's population and
of its wealth. Assume that the citizens of
share the wealth of
equally,and assume that those of
share the wealth of
equally. Find the ratio of the wealth of a citizen of
to the wealth of a citizen of
.
Solution
If country has
of the wealth in the world and
people that means that each person has
of all the wealth in the world. Using a similar argument for Country
we have that each person has
of the wealth In the world. Evaluating the desired fraction gives us
See also
1993 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.