Difference between revisions of "1964 AHSME Problems/Problem 2"
(Created page with "Since there is an x^2 and a y^2, it is a hyperbola. Therefore, it is E.") |
(No difference)
|
Revision as of 14:11, 28 October 2018
Since there is an x^2 and a y^2, it is a hyperbola. Therefore, it is E.
