Difference between revisions of "2021 Fall AMC 10A Problems/Problem 16"
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==Solution 2 (Graphing)== | ==Solution 2 (Graphing)== | ||
| − | + | Let <math>y_1=|\lfloor x \rfloor|</math> and <math>y_2=|\lfloor 1 - x \rfloor|=|\lfloor -(x-1) \rfloor|.</math> Note that <math>y_2</math> is a reflection of <math>y_1</math> about the <math>y</math>-axis, followed by a translation of <math>1</math> unit right. | |
| + | |||
| + | The graph of <math>y_1</math> is shown below: | ||
<asy> | <asy> | ||
/* Made by MRENTHUSIASM */ | /* Made by MRENTHUSIASM */ | ||
| Line 85: | Line 87: | ||
} | } | ||
</asy> | </asy> | ||
| − | The graph of <math> | + | The graph of <math>y_2</math> is shown below: |
<b>DIAGRAM WILL BE READY VERY SOON. APPRECIATE IT IF THERE'S NO EDIT AT THIS PAGE WITHIN THE NEXT HOUR.</b> | <b>DIAGRAM WILL BE READY VERY SOON. APPRECIATE IT IF THERE'S NO EDIT AT THIS PAGE WITHIN THE NEXT HOUR.</b> | ||
Revision as of 14:15, 25 November 2021
Problem
The graph of ![\[f(x) = |\lfloor x \rfloor| - |\lfloor 1 - x \rfloor|\]](http://latex.artofproblemsolving.com/0/8/5/0856042a755ebc88c0261897b7fad311209d9e99.png)
is symmetric about which of the following? (Here 
is the greatest integer not exceeding 
.)
Solution 1 (Piecewise Function)
IN PROGRESS AND WILL FINISH SOON. NO EDIT PLEASE. A MILLION THANKS.
~MRENTHUSIASM
Solution 2 (Graphing)
Let 
and 
Note that 
is a reflection of 
about the 
-axis, followed by a translation of 
unit right.
The graph of is shown below:
![[asy] /* Made by MRENTHUSIASM */ size(250); int xMin = -10; int xMax = 10; int yMin = -10; int yMax = 10; //Draws the horizontal gridlines void horizontalLines() { for (int i = yMin+1; i < yMax; ++i) { draw((xMin,i)--(xMax,i), mediumgray+linewidth(0.4)); } } //Draws the vertical gridlines void verticalLines() { for (int i = xMin+1; i < xMax; ++i) { draw((i,yMin)--(i,yMax), mediumgray+linewidth(0.4)); } } //Draws the horizontal ticks void horizontalTicks() { for (int i = yMin+1; i < yMax; ++i) { draw((-3/16,i)--(3/16,i), black+linewidth(1)); } } //Draws the vertical ticks void verticalTicks() { for (int i = xMin+1; i < xMax; ++i) { draw((i,-3/16)--(i,3/16), black+linewidth(1)); } } //Draws and labels coordinate axes void drawLabelAxes() { draw((xMin,0)--(xMax,0),black+linewidth(1.5),EndArrow(5)); draw((0,yMin)--(0,yMax),black+linewidth(1.5),EndArrow(5)); label("$x$",(xMax,0),(2,0)); label("$y$",(0,yMax),(0,2)); } horizontalLines(); verticalLines(); horizontalTicks(); verticalTicks(); drawLabelAxes(); path P[], Q[]; for (int i = 0; i < 9; ++i) { P[i] = (i,i)--(i+1,i); Q[i] = (-i,i+1)--(-i-1,i+1); } draw(P^^Q,red,"$y=|\lfloor x \rfloor|$"); for (int i = 0; i < 9; ++i) { dot((i,i),red); dot((i+1,i),red,UnFill); dot((-i-1,i+1),red); dot((-i,i+1),red,UnFill); } [/asy]](http://latex.artofproblemsolving.com/a/2/9/a29f992829703f8215a7626ce2f883b2f7d897ca.png)
The graph of is shown below:
DIAGRAM WILL BE READY VERY SOON. APPRECIATE IT IF THERE'S NO EDIT AT THIS PAGE WITHIN THE NEXT HOUR.
Taking the difference, we graph 
as shown below:
DIAGRAM WILL BE READY VERY SOON. APPRECIATE IT IF THERE'S NO EDIT AT THIS PAGE WITHIN THE NEXT HOUR.
Therefore, the answer is 
~MRENTHUSIASM
See Also
| 2021 Fall AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
