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| − | ==Problem==
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| − | A bar graph shows the number of hamburgers sold by a fast food chain each season. However, the bar indicating the number sold during the winter is covered by a smudge. If exactly <math>25\% </math> of the chain's hamburgers are sold in the fall, how many million hamburgers are sold in the winter?
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| − | <asy>
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| − | size(250);
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| − |
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| − | void bargraph(real X, real Y, real ymin, real ymax, real ystep, real tickwidth,
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| − | string yformat, Label LX, Label LY, Label[] LLX, real[] height,pen p=nullpen)
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| − | {
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| − | draw((0,0)--(0,Y),EndArrow);
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| − | draw((0,0)--(X,0),EndArrow);
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| − | label(LX,(X,0),plain.SE,fontsize(9));
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| − | label(LY,(0,Y),plain.NW,fontsize(9));
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| − | real yscale=Y/(ymax+ystep);
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| − |
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| − | for(real y=ymin; y<ymax; y+=ystep)
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| − | {
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| − | draw((-tickwidth,yscale*y)--(0,yscale*y));
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| − | label(format(yformat,y),(-tickwidth,yscale*y),plain.W,fontsize(9));
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| − | }
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| − |
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| − | int n=LLX.length;
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| − | real xscale=X/(2*n+2);
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| − | for(int i=0;i<n;++i)
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| − | {
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| − | real x=xscale*(2*i+1);
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| − | path P=(x,0)--(x,height[i]*yscale)--(x+xscale,height[i]*yscale)--(x+xscale,0)--cycle;
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| − | fill(P,p);
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| − | draw(P);
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| − | label(LLX[i],(x+xscale/2),plain.S,fontsize(10));
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| − | }
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| − | for(int i=0;i<n;++i) draw((0,height[i]*yscale)--(X,height[i]*yscale),dashed);
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| − | }
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| − | string yf="%#.1f";
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| − | Label[] LX={"Spring","Summer","Fall","Winter"};
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| − | for(int i=0;i<LX.length;++i) LX[i]=rotate(90)*LX[i];
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| − | real[] H={4.5,5,4,4};
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| − |
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| − | bargraph(60,50,1,5.1,0.5,2,yf,"season","hamburgers (millions)",LX,H,yellow);
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| − | fill(ellipse((45,30),7,10),brown);
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| − | </asy>
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| − | <math>\text{(A)}\ 2.5 \qquad \text{(B)}\ 3 \qquad \text{(C)}\ 3.5 \qquad \text{(D)}\ 4 \qquad \text{(E)}\ 4.5</math>
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| − |
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| − | ==Solution==
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| − |
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| − | {{Solution}}
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| − |
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| − | ==See Also==
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| − |
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| − | [[1986 AJHSME Problems]]
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