Difference between revisions of "2017 AMC 10B Problems/Problem 6"
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==Problem== | ==Problem== | ||
| − | What is the largest number of solid <math>2\text{in}</math> by <math>2\text{in}</math> by <math>1\text{in}</math> blocks that can fit in a <math>3\text{in}</math> by <math>2\text{in}</math> by <math>3\text{in}</math> box? | + | What is the largest number of solid <math>2\text{ in}</math> by <math>2\text{ in}</math> by <math>1\text{ in}</math> blocks that can fit in a <math>3\text{ in}</math> by <math>2\text{ in}</math> by <math>3\text{ in}</math> box? |
<math>\textbf{(A)}\ 3\qquad\textbf{(B)}\ 4\qquad\textbf{(C)}\ 5\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 7</math> | <math>\textbf{(A)}\ 3\qquad\textbf{(B)}\ 4\qquad\textbf{(C)}\ 5\qquad\textbf{(D)}\ 6\qquad\textbf{(E)}\ 7</math> | ||
Revision as of 11:46, 16 February 2017
Problem
What is the largest number of solid 
by by 
blocks that can fit in a 
by by box?
Solution
We find that the volume of the larger block is 
, and the volume of the smaller block is 
. Dividing the two, we see that only a maximum of 
xx
blocks can fit inside the 
xx block. 
| 2017 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
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| All AMC 10 Problems and Solutions | ||
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