Difference between revisions of "2009 AMC 12B Problems/Problem 16"
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=== Solution 2 === | === Solution 2 === | ||
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== See also == | == See also == | ||
{{AMC12 box|year=2009|ab=B|num-b=15|num-a=17}} | {{AMC12 box|year=2009|ab=B|num-b=15|num-a=17}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 20:07, 16 February 2024
Contents
[hide]Problem
Trapezoid has , , , and . The ratio is . What is ?
Solutions
Solution 1
Extend and to meet at . Then
Thus is isosceles with . Because , it follows that the triangles and are similar. Therefore so
Solution 2
See also
2009 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 15 |
Followed by Problem 17 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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