Difference between revisions of "1965 AHSME Problems/Problem 10"
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Math Kirby (talk | contribs) (fix answer choice) |
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\textbf{(C) }\ x < 3 \ | \textbf{(C) }\ x < 3 \ | ||
\textbf{(D) }\ x > 3 \text{ and }x < - 2 \qquad | \textbf{(D) }\ x > 3 \text{ and }x < - 2 \qquad | ||
− | \textbf{(E) }\ x > 3 \text{ | + | \textbf{(E) }\ x > 3 \text{ or }x < - 2 </math> |
==Solution== | ==Solution== |
Latest revision as of 14:39, 13 November 2024
Problem 10
The statement is equivalent to the statement:
Solution
To solve this problem, we may begin by factoring as . This is an upward opening parabola, therefore the solutions to are between the roots of the equation. That means our solutions are all such that , or simply .
See Also
1965 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.