Difference between revisions of "2024 AMC 10B Problems/Problem 8"
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~ Pi Academy | ~ Pi Academy | ||
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+ | ==Video Solution 2 by SpreadTheMathLove== | ||
+ | https://www.youtube.com/watch?v=24EZaeAThuE | ||
==See also== | ==See also== | ||
{{AMC10 box|year=2024|ab=B|num-b=7|num-a=9}} | {{AMC10 box|year=2024|ab=B|num-b=7|num-a=9}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 13:55, 14 November 2024
Contents
[hide]Problem
Let be the product of all the positive integer divisors of . What is the units digit of ?
Solution 1
The factors of are: . Multiply unit digits to get
Solution 2
The product of the factors of a number is , where is the number of positive divisors of . We see that which has factors, so the product of the divisors of is
But we only need the last digit of this, which is the same as the last digit of . The answer is .
Video Solution 1 by Pi Academy (Fast and Easy ⚡🚀)
https://youtu.be/QLziG_2e7CY?feature=shared
~ Pi Academy
Video Solution 2 by SpreadTheMathLove
https://www.youtube.com/watch?v=24EZaeAThuE
See also
2024 AMC 10B (Problems • Answer Key • Resources) | ||
Preceded by Problem 7 |
Followed by Problem 9 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.