Difference between revisions of "2007 AMC 12B Problems/Problem 1"
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==See Also== | ==See Also== | ||
{{AMC12 box|year=2007|ab=B|before=First question|num-a=2}} | {{AMC12 box|year=2007|ab=B|before=First question|num-a=2}} | ||
| − | {{AMC10 box|year=2007|ab=B|before=First | + | {{AMC10 box|year=2007|ab=B|before=First Problem|num-a=2}} |
[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] | ||
Revision as of 19:46, 9 October 2011
- The following problem is from both the 2007 AMC 12B #1 and 2007 AMC 10B #1, so both problems redirect to this page.
Problem
Isabella's house has 3 bedrooms. Each bedroom is 12 feet long, 10 feet wide, and 8 feet high. Isabella must paint the walls of all the bedrooms. Doorways and windows, which will not be painted, occupy 60 square feet in each bedroom. How many square feet of walls must be painted?
Solution
There are four walls in each bedroom, since she can't paint floors or ceilings. So we calculate the number of square feet of wall there is in one bedroom:
![\[12*8+12*8+10*8+10*8-60=160+192-60=292\]](http://latex.artofproblemsolving.com/2/b/b/2bbeef4dfcc3bee434d64ff03a1547e9b0f6e747.png)
We have three bedrooms, so she must paint 
square feet of wall.
See Also
| 2007 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First question |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
| 2007 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
