2016 AMC 8 Problems/Problem 22
Contents
[hide]Problem
Rectangle below is a rectangle with . The area of the "bat wings" (shaded area) is
Solution 2
The area of trapezoid is . Next, we find the height of each triangle to calculate their area. The two non-colored isosceles triangles are similar, and are in a ratio by AA similarity (alternate interior and vertical angles) so the height of the larger is while the height of the smaller one is Thus, their areas are and . Subtracting these areas from the trapezoid, we get . Therefore, the answer to this problem is
Video Solution (CREATIVE THINKING + ANALYSIS!!!)
~Education, the Study of Everything
Video Solutions
- https://youtu.be/q3MAXwNBkcg ~savannahsolver
Video Solution by OmegaLearn
https://youtu.be/FDgcLW4frg8?t=4448 ~ pi_is_3.14
See Also
2016 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 21 |
Followed by Problem 23 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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