Derivative/Definition
Differential Calculus is a sub-field of Calculus that primarily focuses on how functions change as the input changes. In Differential Calculus we usually use Differentiation, or the process of finding the derivative.
Derivative represents the slope of the slope of the line tangent to a function at some point. We can also find critical points with the first and second derivative.
Long method for Derivative: Let the function be . Find the First Derivative.
If we imagine the secant line intersecting a curve at the points
and
. Then we can change this to the tangent by setting
on top of
. Let us call the horizontal or vertical distance as
.
After canceling like terms we should have all terms contain an . We can then cancel out the
and set
. Our end result is the first-derivative.
The first derivative is denoted as .
This would be some tedious work so instead there is a much nicer way to find the derivative.
Let . Let
1. Find the .
Any function like this is:
g'(x)$.
Breaking apart on what we used above.$ (Error compiling LaTeX. Unknown error_msg)g'(x)=t \cdot x^{t-1}+(n-1) \cdot x^{n-2}+ 5 \cdot 3 \cdot x^2$$ (Error compiling LaTeX. Unknown error_msg)g'(x)=t \cdot x^{t-1}+(n-1) \cdot x^{n-2}+15x^2f(x)=-147
f'(x)$.
If the function$ (Error compiling LaTeX. Unknown error_msg)f(x)0$.
Notation:$ (Error compiling LaTeX. Unknown error_msg)f'(x)f(x)
f(x)
f'(x)
\frac{d}{dx} f(x)
\frac{d^n}{dx^n} f(x)$.
Maximum and Minimum: We can use the first derivative to determine the maximum and the minimum points of a graph.
If$ (Error compiling LaTeX. Unknown error_msg)f'(x)=6x^2-246x^2-24=
x=2
x=-2
f(x)$if it was given, and the one with the higher y-coordinate is the maximum, while the smaller y-coordinate gives the minimum.
Below are problems for Part I. In Part II(see link below) we will begin to actually "start" the calculus with this.
== Problems for Part I ==$ (Error compiling LaTeX. Unknown error_msg)\boxed{\text{Problem 1}}f(x)
f(x)=2x^2-15x+7
\boxed{\text{Solution 1}}
f'(x)=2 \cdot 2 \cdot x^1-15 \cdot 1 \cdot x^0+0$$ (Error compiling LaTeX. Unknown error_msg)f'(x)=4x-15
\boxed{\text{Problem 2}}
f(x)=3x^3-5x^2+12
(-1,14)
\boxed{\text{Solution 2}}$:
We will take the first derivative to determine the slope of the tangent line.$ (Error compiling LaTeX. Unknown error_msg)f'(x)=9x^2-10x-1
x
f'(x)=9+10=19
19$.
Let the equation be:$ (Error compiling LaTeX. Unknown error_msg)y=19x+b$.
Plugging$ (Error compiling LaTeX. Unknown error_msg)(-1,14)14=-19+b$$ (Error compiling LaTeX. Unknown error_msg)\implies b=30
\therefore
y=19x+33
\boxed{\text{Problem 3}}
f(x)=x^n$$ (Error compiling LaTeX. Unknown error_msg)\boxed{\text{Solution 3}}
\frac{d}{dx} f(x)=nx^{n-1}$$ (Error compiling LaTeX. Unknown error_msg)\frac{d^2}{dx^2} f(x)=n(n-1) x^{n-2}$$ (Error compiling LaTeX. Unknown error_msg)\vdots$$ (Error compiling LaTeX. Unknown error_msg)\frac{d^{n}}{dx^{n}} f(x)=n(n-1)(n-2) \cdots 1$$ (Error compiling LaTeX. Unknown error_msg)\frac{d^{n}}{dx^{n}} f(x)=n!$$ (Error compiling LaTeX. Unknown error_msg)\therefore
f(x)
n!$.