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- ...07 508 510 511 512 513 514 515 516 517 518 519 520 522 524 525 526 527 528 529 530 531 532 533 534 535 536 537 538 539 540 542 543 544 545 546 548 549 5506 KB (350 words) - 11:58, 26 September 2023
- ...term, so our answer is the biggest non-square and non-cube less than <math>529</math>, which is <math>\boxed{528}</math>. ...Solution 1, but to get the intuition why we chose to consider <math>23^2 = 529</math>, consider this:2 KB (283 words) - 22:11, 25 June 2023
- <math>4 , 9 , 25 , 49 , 121, 169 , 289 , 361 , 529</math>8 KB (1,245 words) - 09:53, 4 February 2025
- ...lution is <math>\frac{23^3 - 1}{22} = \frac{(23 - 1)(23^2 + 23 + 1)}{22} = 529 + 23 + 1 = 553</math>.3 KB (428 words) - 17:04, 4 December 2020
- t + \frac {1}{r} &= \frac {529}{102}.\end{align*}</cmath>6 KB (909 words) - 06:27, 12 October 2022
- <cmath>448 + 81 = \boxed{529}</cmath> ...1} = \frac {448}{81}</math>, yielding an answer of <math>448 + 81 = \boxed{529}</math>.3 KB (465 words) - 21:07, 17 December 2021
- <cmath>441, 484, 529,576,625,676,729,784,841,900,961</cmath>We see that <math>484</math> and <ma3 KB (547 words) - 14:39, 1 December 2024
- ...</math> and <math>\sqrt{96+961} = \sqrt{1057}</math>. Since <math>\sqrt{96+529}<\sqrt{96+961}</math>, <math>25</math> is the shorter length*, so the answe4 KB (652 words) - 08:18, 23 September 2021
- | 222 || iForgot || 6 || 3078.529 || 513.088 | 115 || hashtagmath || 46 || 3934.349 || 85.529163 KB (7,283 words) - 18:16, 13 February 2025
- ...{105}{2}-\frac{529}{3}-207-\frac{140}{9}\right)-\left(-\frac{105}{2}-\frac{529}{9}-105-\frac{92}{3}-\frac{92}{3}\right)\right|</math> <math>=\left|-\frac{232}{9}-\frac{1373}{6}-207+\frac{529}{9}+\frac{184}{3}+105+\frac{105}{2}\right|</math>6 KB (895 words) - 15:37, 14 December 2024
- #52981 bytes (1 word) - 14:28, 15 August 2020
- <math>(129600 + 721) - (129600 + 192) = 529 = 23^2</math>26 KB (4,271 words) - 11:26, 22 February 2025
- ...lements are: n+1=9, 2n+1=17, 3n+1=25, and the only prime factors of 49,161,529 are 7 and 23, therefore they are indecomposable, valid.3 KB (610 words) - 11:25, 2 February 2025
- ...>y=\frac{a}{2}</math>. Then we substitute and get <math>x^2-100=\frac{(a^2-529)}{4}</math>. Finally we multiply by 4 and get <math>4x^2-a^2=-129, a^2-4x^29 KB (1,517 words) - 06:37, 5 November 2024
- ...+2^2+\left(\dfrac{23}4\right)^2}=\sqrt{8+\dfrac{529}{16}}=\sqrt{\dfrac{128+529}{16}}=\dfrac{\sqrt{657}}4</math>. This is the diameter; we halve it to find <cmath>r^2=(128+529)/64</cmath>15 KB (2,495 words) - 08:46, 15 February 2025