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- ...combinatorics, and number theory, along with sets of accompanying practice problems at the end of every section. ...88606&sprefix=after+school+maths+%2Caps%2C268&sr=8-2 100 Challenging Maths Problems]24 KB (3,198 words) - 19:44, 4 December 2024
- ...Examples include the [[Monty Hall paradox]] and the [[birthday problem]]. Probability can be loosely defined as the chance that an event will happen. == Introductory Probability ==4 KB (590 words) - 10:52, 28 September 2024
- {{AMC12 Problems|year=2004|ab=A}} [[2004 AMC 12A Problems/Problem 1|Solution]]13 KB (1,953 words) - 23:31, 25 January 2023
- {{AMC12 Problems|year=2002|ab=B}} [[2002 AMC 12B Problems/Problem 1|Solution]]10 KB (1,547 words) - 03:20, 9 October 2022
- {{AMC12 Problems|year=2003|ab=B}} [[2003 AMC 12B Problems/Problem 1|Solution]]13 KB (1,987 words) - 17:53, 10 December 2022
- {{AMC12 Problems|year=2004|ab=B}} [[2004 AMC 12B Problems/Problem 1|Solution]]13 KB (2,049 words) - 12:03, 19 February 2020
- {{AIME Problems|year=2005|n=II}} [[2005 AIME II Problems/Problem 1|Solution]]7 KB (1,119 words) - 20:12, 28 February 2020
- {{AIME Problems|year=2004|n=II}} [[2004 AIME II Problems/Problem 1|Solution]]9 KB (1,410 words) - 04:05, 20 February 2019
- {{AIME Problems|year=2000|n=I}} [[2000 AIME I Problems/Problem 1|Solution]]7 KB (1,204 words) - 02:40, 4 January 2023
- {{AIME Problems|year=2003|n=I}} [[2003 AIME I Problems/Problem 1|Solution]]6 KB (965 words) - 15:36, 8 September 2019
- {{AIME Problems|year=2002|n=II}} [[2002 AIME II Problems/Problem 1|Solution]]7 KB (1,177 words) - 14:42, 11 August 2023
- ...the vertex at its opposite end. Let <math>p = \frac{n}{729}</math> be the probability that the bug is at vertex <math>A</math> when it has crawled exactly <math> For all nonnegative integers <math>k,</math> let <math>P(k)</math> be the probability that the bug is at vertex <math>A</math> when it has crawled exactly <math>19 KB (3,128 words) - 20:38, 23 July 2024
- Let <math>p_{}</math> be the [[probability]] that, in the process of repeatedly flipping a fair coin, one will encount ...is <math>1/4</math>, the total probability is that <math>3/2</math> of the probability given that the sequence starts with an <tt>H</tt>.7 KB (1,087 words) - 12:09, 17 November 2024
- [[Mock AIME 1 2006-2007 Problems/Problem 1|Solution]] [[Mock AIME 1 2006-2007 Problems/Problem 2|Solution]]8 KB (1,355 words) - 13:54, 21 August 2020
- [[2007 iTest Problems/Problem 1|Solution]] [[2007 iTest Problems/Problem 2|Solution]]30 KB (4,794 words) - 22:00, 8 May 2024
- {{AMC10 Problems|year=2004|ab=A}} [[2004 AMC 10A Problems/Problem 1|Solution]]15 KB (2,092 words) - 19:32, 15 April 2024
- {{AIME Problems|year=2007|n=II}} [[2007 AIME II Problems/Problem 1|Solution]]9 KB (1,435 words) - 00:45, 6 December 2021
- {{AMC12 Problems|year=2007|ab=B}} [[2007 AMC 12B Problems/Problem 1 | Solution]]12 KB (1,814 words) - 11:58, 19 February 2020
- ...oves <math>5</math> cm in a straight line to <math>C</math>. What is the [[probability]] that <math>AC < 7</math>? It follows that <math>0 < \alpha < \frac {\pi}3</math>, and the probability is <math>\frac{\pi/3}{\pi} = \boxed{\textbf{(D) } \frac13 }</math>.3 KB (461 words) - 09:23, 20 September 2024
- [[2008 iTest Problems/Problem 1|Solution]] [[2008 iTest Problems/Problem 2|Solution]]71 KB (11,749 words) - 11:39, 20 November 2024