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- Notice that <math>252=2^2\cdot 3^2\cdot 7</math>. Because <math>b=2a</math> and <m #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]]2 KB (296 words) - 00:17, 12 July 2021
- #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]] #[[2021 JMPSC Sprint Answer Key|2021 JMPSC Sprint Answer Key]]1 KB (195 words) - 09:09, 12 July 2021
- #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]] #[[2021 JMPSC Sprint Answer Key|2021 JMPSC Sprint Answer Key]]1 KB (178 words) - 09:41, 12 July 2021
- #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]] #[[2021 JMPSC Sprint Answer Key|2021 JMPSC Sprint Answer Key]]1,017 bytes (175 words) - 16:12, 11 July 2021
- We notice that In addition, we notice that2 KB (209 words) - 16:25, 11 July 2021
- #[[2021 JMPSC Sprint Problems|Other 2021 JMPSC Sprint Problems]] #[[2021 JMPSC Sprint Answer Key|2021 JMPSC Sprint Answer Key]]4 KB (634 words) - 09:53, 12 July 2021
- Notice that since <math>x</math> and <math>y</math> are both integers, <math>x+y</ #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]]2 KB (300 words) - 16:15, 12 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]937 bytes (127 words) - 16:22, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]2 KB (333 words) - 16:24, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]2 KB (304 words) - 00:19, 12 July 2021
- [[2021 JMPSC Accuracy Problems/Problem 1|Solution]] [[2021 JMPSC Accuracy Problems/Problem 2|Solution]]5 KB (729 words) - 17:41, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]1 KB (178 words) - 16:24, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]1 KB (196 words) - 16:24, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]1 KB (205 words) - 16:23, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]804 bytes (106 words) - 09:04, 12 July 2021
- Notice that since <math>\overline{AC}</math> bisects a pair of opposite angles in #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]]1 KB (164 words) - 16:53, 11 July 2021
- Notice that <math>C</math> can only be <math>0</math>, <math>1</math>, and <math>5 ...have <math>AB0 \cdot 3 = 790</math>, and so <math>AB \cdot 3 = 79</math>. Notice that <math>79</math> is not divisible by <math>3</math>, so <math>C=0</math2 KB (332 words) - 09:42, 18 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]718 bytes (98 words) - 16:23, 11 July 2021
- #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]] #[[2021 JMPSC Accuracy Answer Key|2021 JMPSC Accuracy Answer Key]]1 KB (170 words) - 16:23, 11 July 2021
- ...rs that form an arithmetic progression is the median of the numbers. Also, notice that to maximize the average of three numbers, we need to maximize the numb #[[2021 JMPSC Accuracy Problems|Other 2021 JMPSC Accuracy Problems]]980 bytes (133 words) - 12:11, 13 July 2021