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- ...<math> M </math> is in the interior of the triangle so that <math> \angle MAC = 7^\circ </math> and <math> \angle MCA = 23^\circ. </math> Find the number {{MAA Notice}}6 KB (965 words) - 15:36, 8 September 2019
- ...math>BC = a,</math> and let <math>AC = b</math>; let <math>\alpha = \angle MAC</math>, and let <math>\beta = \angle BNC</math>. {{MAA Notice}}11 KB (1,722 words) - 08:49, 13 September 2023
- ...<math> M </math> is in the interior of the triangle so that <math> \angle MAC = 7^\circ </math> and <math> \angle MCA = 23^\circ. </math> Find the number {{MAA Notice}}7 KB (1,082 words) - 01:08, 30 September 2024
- Notice that the function must be declared a pair since it returns a pair, and each ...ws (<tt>C:\Program Files\Asymptote</tt> by default) and <tt>~/.asy</tt> on Mac where <tt>~</tt> is <tt>/Users/YOUR_USERNAME</tt>. Then <tt>import MyMacro3 KB (532 words) - 09:48, 4 October 2024
- ...rmation pane on a package's homepage on CTAN. On <math>\text{\TeX\ Live or Mac\TeX}</math> do on the terminal "sudo tlmgr install <package-name>". For <ma Notice that we only have to include mylay with \usepackage; mycommands is included10 KB (1,656 words) - 08:33, 21 September 2024
- ...math>\angle NBC = \angle NAC = \alpha</math> and <math>\angle MBC = \angle MAC = 90^\circ - \alpha</math>. Additionally <math>NB = \frac{4}{5}</math> and {{MAA Notice}}11 KB (1,862 words) - 20:23, 23 May 2024
- ...ions, click on the link that corresponds to your computer type (Windows or Mac, 32-bit or 64-bit -- if you're not sure, use the 32-bit version.) Some brow * On a Mac, IDLE should be in the Applications folder.14 KB (2,363 words) - 18:07, 20 February 2025
- ...gle <math>XAX'</math> is equilateral and that <math>XX' = 5.</math> We now notice that <math>XC = 3</math> and <math>X'C = 4</math> which tells us that angle <cmath>\angle MXC+\angle LXB = \angle MAC + \angle LAB = 180 – \angle BAC = 90</cmath>13 KB (2,146 words) - 12:15, 29 December 2024
- ...\angle MAB=10^\circ</math>, <math>\angle MBA=20^\circ</math>, <math>\angle MAC=40^\circ</math> and <math>\angle MCA=30^\circ</math>. Prove that the triang {{MAA Notice}}2 KB (408 words) - 07:10, 19 July 2016
- ...ngle MAB=10^\circ </math>, <math>\angle MBA=20^\circ</math> , <math>\angle MAC= 40^\circ</math> and <math>\angle MCA=30^\circ</math>. Prove that the trian Notice that5 KB (744 words) - 15:35, 28 June 2021
- ...And it is also true that triangle MAC is half of triangle DAC, so triangle MAC would just be 1/4 of the whole rectangle. Since the rectangle's area is 48, {{MAA Notice}}3 KB (436 words) - 10:38, 20 June 2024
- ...</math> and <math>GQ</math> intersect at <math>M</math>, then <math>\angle MAC = 90^{\circ}.</math> Notice that since <math>A</math> is the intersection of <math>(EDQ)</math> and <ma6 KB (626 words) - 09:46, 27 August 2023
- {{MAC Notice}}3 KB (538 words) - 13:38, 26 January 2021
- {{MAC Notice}}2 KB (281 words) - 12:49, 4 January 2021
- ...=\angle CBT=\angle BCT</math>, we have <math>\cos A=\tfrac{11}{16}</math>. Notice that <math>AXTY</math> is cyclic, so <math>\angle XTY=180^{\circ}-A</math>, (Notice that <math>MXTY</math> is a parallelogram, which is an important theorem in9 KB (1,492 words) - 21:59, 11 January 2025
- {{MAC Notice}}1 KB (134 words) - 23:48, 4 September 2020
- {{MAC Notice}}648 bytes (99 words) - 13:51, 22 December 2023
- {{MAC Notice}}2 KB (400 words) - 16:40, 2 October 2024
- {{MAC Notice}}1 KB (228 words) - 23:03, 4 September 2020
- {{MAC Notice}}2 KB (282 words) - 20:48, 17 May 2023