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Page title matches
- == Problem ==2 KB (302 words) - 01:57, 18 October 2024
- {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #1]] and [[2001 AMC 10 Problems|2001 AMC 10 #3]]}} == Problem ==904 bytes (136 words) - 16:10, 15 July 2024
- {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #2]] and [[2001 AMC 10 Problems|2001 AMC 10 #6]]}} == Problem ==1,007 bytes (165 words) - 20:31, 27 October 2024
- {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #3]] and [[2001 AMC 10 Problems|2001 AMC 10 #9]]}} ==Problem==2 KB (221 words) - 21:40, 15 July 2024
- {{duplicate|[[2000 AMC 12 Problems|2000 AMC 12 #1]] and [[2000 AMC 10 Problems|2000 AMC 10 #1]]}} ==Problem==2 KB (320 words) - 19:37, 30 November 2024
- == Problem ==911 bytes (147 words) - 18:54, 13 December 2017
- == Problem ==1 KB (239 words) - 13:29, 17 December 2024
- {{duplicate|[[2005 AMC 12B Problems|2005 AMC 12B #12]] and [[2005 AMC 10B Problems|2005 AMC 10B #16]]}} == Problem ==2 KB (322 words) - 02:57, 11 November 2024
- == Problem == <!-- [[Image:2006 AMC 10A-12.GIF]] -->3 KB (424 words) - 10:14, 17 December 2021
- ...ate|[[2006 AMC 12A Problems|2006 AMC 12A #12]] and [[2006 AMC 10A Problems/Problem 14|2006 AMC 10A #14]]}} == Problem ==2 KB (292 words) - 11:56, 17 December 2021
- == Problem == ...^2</math> equal and solving for <math>x</math> (it is helpful to scale the problem down by a factor of 50 first), we get <math>x = 250\pm 50\sqrt{7}</math>. S13 KB (2,080 words) - 13:14, 23 July 2024
- == Problem ==4 KB (647 words) - 02:29, 4 May 2021
- == Problem ==2 KB (303 words) - 18:43, 16 October 2024
- == Problem ==3 KB (431 words) - 23:21, 4 July 2013
- == Problem ==2 KB (412 words) - 18:23, 1 January 2024
- == Problem == Since this is a recursive problem, list out the functions f(2) and f(7) and figure out what is equivalent wit3 KB (588 words) - 14:37, 22 July 2020
- == Problem == ...math>(x+x^2+x^3)^n</math>, so the generating function of interest for this problem is <math>(x+x^2+x^3)^7</math>. Our goal is to find the coefficients of ever19 KB (3,128 words) - 21:38, 23 July 2024
- == Problem == ...ve more than 4 elements, otherwise its sum would be at most <math>15+14+13+12=54</math>.2 KB (382 words) - 19:52, 20 January 2025
- == Problem ==4 KB (673 words) - 19:48, 28 December 2023
- == Problem == [[Image:1988_AIME-12.png]]4 KB (743 words) - 21:02, 8 December 2024
Page text matches
- <cmath>5-12-13</cmath> <cmath>12-35-37</cmath>6 KB (978 words) - 12:02, 6 March 2025
- == Problem == ...p with <math>12x^3</math>. Taking the answer choices and dividing by <math>12</math>, we get <math>(A) 4</math>,1 KB (216 words) - 00:23, 6 September 2024
- == Problem == ...+ 2 + 3 \cdots + 10 = 55.</math> Knowing this, we can say that <math>11 + 12 \cdots + 20 = 155</math> and <math>21 + \cdots +30 =255</math> and so on. T2 KB (395 words) - 23:29, 3 December 2024
- == Problem == ...the shaded area is <math>(8 \cdot 5) - 2(\frac{15}{2}) - 2(6) = 40 - 15 - 12 = 13</math>. Since the desired area is half the shaded region, our area is8 KB (1,016 words) - 00:17, 31 December 2023
- == Problem == {{AMC10 box|year=2016|ab=A|num-b=12|num-a=14}}2 KB (402 words) - 14:54, 25 June 2023
- * [[Noetic Learning Math Contest]] - semiannual problem solving contest for elementary and middle school students. [Grades 2-8] ...athcon.org MathCON] hosts annual math competition for students in grades 4-12.5 KB (512 words) - 23:26, 13 January 2025
- * [https://www.hardestmathproblem.org Hardest Math Problem] math contest for grades 5-8 with great prizes. * [[Noetic Learning Math Contest]]: a popular problem-solving contest for students in grades 2-8.7 KB (805 words) - 23:27, 13 January 2025
- **[[AMC 12]] ...athcon.org MathCON] hosts annual math competition for students in grades 4-12, with more than 200,000 participants since 2008.6 KB (625 words) - 23:27, 13 January 2025
- * [[Art of Problem Solving Academy]] (Locations Nationwide) [https://aopsacademy.org/courses/s * [[MehtA+ AI in Visual Arts Camp]] is a mini-bootcamp for grades 5-12 [https://mehtaplustutoring.com/ai-in-visual-arts/ Website]14 KB (1,920 words) - 12:04, 19 February 2025
- ...cluding Art of Problem Solving, the focus of MATHCOUNTS is on mathematical problem solving. Students are eligible for up to three years, but cannot compete be ...ics]]. The focus of MATHCOUNTS curriculum is in developing [[mathematical problem solving]] skills.11 KB (1,578 words) - 15:58, 15 March 2025
- *[[Doane triMATHlon Math Contest]]. Takes place at Doane University for 9-12 graders, includes material up to Algebra II. [https://www.doane.edu/trimath ...]. Consists of two problem solving rounds and a speed round - for grades 9-12.2 KB (200 words) - 10:11, 29 December 2020
- ...idual articles often have sample problems and solutions for many levels of problem solvers. Many also have links to books, websites, and other resources rele ...ets [//competifyhub.com/resources/ Free Competition Resources for Grades 1-12]14 KB (1,913 words) - 23:52, 6 March 2025
- '''David Patrick''' is a teacher and curriculum developer for [[Art of Problem Solving]] (AoPS). Dr. Patrick joined AoPS in 2004. ...erican High School Mathematics Examination]] (AHSME), now called the [[AMC 12]]. That same year, Patrick was a winner of the [[USA Mathematical Olympiad3 KB (379 words) - 11:18, 27 September 2024
- These '''math books''' are recommended by [[Art of Problem Solving]] administrators and members of the [{{SERVER}}/community AoPS Comm * Intermediate is recommended for students who can expect to pass the AMC 10/12.23 KB (3,036 words) - 16:38, 1 March 2025
- ...ks''' page is for compiling a list of [[textbook]]s for mathematics -- not problem books, contest books, or general interest books. See [[math books]] for mo * Intermediate is recommended for students grades 9 to 12.7 KB (902 words) - 15:34, 13 January 2025
- ...n mathematics and also to help middle school students learn [[mathematical problem solving]]. ...region=USA|type=Multiple Choice|difficulty=1 - 2|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 2}}4 KB (584 words) - 19:59, 19 February 2025
- ...'''American Mathematics Contest 10''' ('''AMC 10'''), along with the [[AMC 12]], are the first exams in the series of exams used to challenge bright stud High scoring AMC 10 and AMC 12 students are invited to take the [[American Invitational Mathematics Examin4 KB (596 words) - 04:53, 3 February 2025
- The '''American Mathematics Contest 12''' ('''AMC 12'''), along with the [[AMC 10]], are the first exams in the series of exams High scoring AMC 12 students are invited to take the more challenging [[American Invitational M5 KB (646 words) - 04:52, 3 February 2025
- ...ica Mathematics Olympiad]] (USAMO) for qualification from taking the [[AMC 12]] or [[United States of America Junior Mathematical Olympiad]] (USAJMO) for ...ministered by the [[Mathematical Association of America]] (MAA). [[Art of Problem Solving]] (AoPS) is a proud sponsor of the AMC.5 KB (669 words) - 17:19, 11 March 2025
- ...th Jam''' is a free online class or information session hosted by [[Art of Problem Solving]] in the [[AoPS Schoolhouse|classroom]]. ...sessions for discussion of the problems from each year's [[AMC 10]], [[AMC 12]], and [[AIME]] exams.891 bytes (116 words) - 18:36, 31 January 2025