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- ==[[Triangle]] Congruence== === SSS Congruence ===10 KB (1,655 words) - 15:56, 17 September 2024
- ...h> and <math>BPM</math> are [[congruent (geometry) | congruent]], by [[SAS congruence]]. Hence the segments <math>PA</math> and <math>PB</math> are congruent, m ...the triangles <math>PAM</math> and <math>PBM</math> are congruent by [[SSS congruence]], so the angles <math>PAM</math> and <math>PBM</math> are congruent. Sinc2 KB (367 words) - 14:20, 1 January 2014
- It's not hard to see that the four faces are congruent from SSS Congruence. Without loss of generality, assume that <math>AB\leq BC \leq CA</math>. No ...obtuse. WLOG, assume <math>\angle BAC</math> is an obtuse angle. Using SSS congruence to prove that all four faces of the tetrahedron are congruent also shows th8 KB (1,458 words) - 22:42, 27 February 2022
- <math>\triangle BAO\cong\triangle BCO</math> by SSS congruence, so <math>\angle ABO = \angle CBO = \frac{60}{2} = 30 ^\circ</math>. Since4 KB (576 words) - 18:59, 25 November 2023
- ...ong \overline{OD}</math> as they are both radii of the same circle. By SSS Congruence, we have that <math>\triangle OBC \cong \triangle OCD</math>, so we have th ...les, and triangle <math>AOB</math> is congruent to <math>DOC</math> by SSS congruence. Therefore, <math>\angle BAD = 180 - \angle BCD = 180-(\angle BCO + \angle25 KB (3,940 words) - 18:48, 24 October 2024
- ...AC</math> = <math>AC</math> and <math>AD</math> = <math>AD'</math>, by SSS Congruence, <math>ACD</math> and <math>ACD'</math> are congruent, so <math>[ACD]</math3 KB (554 words) - 07:31, 2 July 2020
- ...[ACD] + [BCD])</math> must the volume. Each face has the same area by SSS congruence, and by Heron's it is <math>\frac{1}{4}\sqrt{(a + b + c)(a + b - c)(c + (a-17 KB (2,702 words) - 14:43, 28 November 2024