1950 AHSME Problems/Problem 10

Problem

After rationalizing the numerator of $\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}}$ , the denominator in simplest form is:

$\textbf{(A)}\ \sqrt{3}(\sqrt{3}+\sqrt{2})\qquad\textbf{(B)}\ \sqrt{3}(\sqrt{3}-\sqrt{2})\qquad\textbf{(C)}\ 3-\sqrt{3}\sqrt{2}\qquad\\ \textbf{(D)}\ 3+\sqrt6\qquad\textbf{(E)}\ \text{None of these answers}$

Solution

To rationalize the numerator, multiply by the conjugate.

$\frac{\sqrt3 - \sqrt2}{\sqrt3}\cdot \frac{\sqrt3 + \sqrt2}{\sqrt3 + \sqrt2} = \frac{1}{3+\sqrt6}.$

The denominator is $\boxed{\mathrm{(D)}\text{ } 3+\sqrt6 .}$

1950 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 8	Followed by Problem 10
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1950 AHSME Problems/Problem 10

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