Difference between revisions of "1950 AHSME Problems/Problem 36"

m (Problem)
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==Solution==
 
==Solution==
Since there is a 20% off sale, then the new price is <math>0.8\cdot2.50</math>. Karl buys five of them, so the amount saved is the price he had to pay with the 20% sale subtracted from the price he had to pay with no sale:
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Since there is a 20% off sale, then the new price is <math>0.8\cdot2.50</math>. Albert buys five of them, so the amount saved is the price he had to pay with the 20% sale subtracted from the price he had to pay with no sale:
  
 
<math>(5\cdot2.50)-(5\cdot0.8\cdot2.50)=(5\cdot2.50)-(4\cdot2.50)</math>
 
<math>(5\cdot2.50)-(5\cdot0.8\cdot2.50)=(5\cdot2.50)-(4\cdot2.50)</math>
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<math>=2.50</math>
 
<math>=2.50</math>
 
<math>\text{Answer: }\boxed{\mathbf{(C)}}</math>
 
<math>\text{Answer: }\boxed{\mathbf{(C)}}</math>
 
  
 
==See Also==
 
==See Also==

Revision as of 14:14, 19 April 2015

Problem

A merchant buys goods at $25\%$ off the list price. He desires to mark the goods so that he can give a discount of $20\%$ on the marked price and still clear a profit of $25\%$ on the selling price. What percent of the list price must he mark the goods?

$\textbf{(A)}\ 125\% \qquad \textbf{(B)}\ 100\% \qquad \textbf{(C)}\ 120\% \qquad \textbf{(D)}\ 80\% \qquad \textbf{(E)}\ 75\%$

Solution

Since there is a 20% off sale, then the new price is $0.8\cdot2.50$. Albert buys five of them, so the amount saved is the price he had to pay with the 20% sale subtracted from the price he had to pay with no sale:

$(5\cdot2.50)-(5\cdot0.8\cdot2.50)=(5\cdot2.50)-(4\cdot2.50)$ $=(5-4)(2.50)$ $=2.50$ $\text{Answer: }\boxed{\mathbf{(C)}}$

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 35
Followed by
Problem 37
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All AHSME Problems and Solutions

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