1950 AHSME Problems/Problem 46

Revision as of 23:05, 25 November 2011 by Evanyao10 (talk | contribs)

If you double sides $AB$ and $A$C, they become $24$ and $14$ respectively. If $BC$ remains $10$, then this triangle has area $0$ because ${14} + {10} = {24}$, so two sides overlap the third side. Therefore the answer is (E)

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