Difference between revisions of "1950 AHSME Problems/Problem 7"

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==Solution==
 
==Solution==
  
By placing the digit <math>1</math> after a two digit number, you are changing the units place to <math>1</math> and moving everything else up a place. Therefore the answer is <math>\boxed{100t+10u+1.}</math>
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By placing the digit <math>1</math> after a two digit number, you are changing the units place to <math>1</math> and moving everything else up a place. Therefore the answer is <math>\boxed{\textbf{(C)}\ 100t+10u+1}</math>.
  
 
==See Also==
 
==See Also==

Revision as of 17:25, 20 June 2012

Problem

If the digit $1$ is placed after a two digit number whose tens' digit is $t$, and units' digit is $u$, the new number is:

$\textbf{(A)}\ 10t+u+1\qquad\textbf{(B)}\ 100t+10u+1\qquad\textbf{(C)}\ 100t+10u+1\qquad\textbf{(D)}\ t+u+1\qquad\\ \textbf{(E)}\ \text{None of these answers}$

Solution

By placing the digit $1$ after a two digit number, you are changing the units place to $1$ and moving everything else up a place. Therefore the answer is $\boxed{\textbf{(C)}\ 100t+10u+1}$.

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
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All AHSME Problems and Solutions