1950 AHSME Problems/Problem 7

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Problem

If the digit $1$ is placed after a two digit number whose tens' digit is $t$, and units' digit is $u$, the new number is:

$\textbf{(A)}\ 10t+u+1\qquad\textbf{(B)}\ 100t+10u+1\qquad\textbf{(C)}\ 100t+10u+1\qquad\textbf{(D)}\ t+u+1\qquad\\ \textbf{(E)}\ \text{None of these answers}$

Solution

By placing the digit $1$ after a two digit number, you are changing the units place to $1$ and moving everything else up a place. Therefore the answer is $\boxed{100t+10u+1.}$

See Also

1950 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
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