Difference between revisions of "1951 AHSME Problems/Problem 26"

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Unsolved
 
Unsolved
  
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{{AHSME 50p box|year=1951|num-b=25|num-a=27}}  
 
{{AHSME 50p box|year=1951|num-b=25|num-a=27}}  

Revision as of 22:39, 10 November 2013

Problem

In the equation $\frac {x(x - 1) - (m + 1)}{(x - 1)(m - 1)} = \frac {x}{m}$ the roots are equal when

$\textbf{(A)}\ m = 1\qquad\textbf{(B)}\ m =\frac{1}{2}\qquad\textbf{(C)}\ m = 0\qquad\textbf{(D)}\ m =-1\qquad\textbf{(E)}\ m =-\frac{1}{2}$

Solution

Unsolved

See Also

1951 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 25
Followed by
Problem 27
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
All AHSME Problems and Solutions

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