# Difference between revisions of "1953 AHSME Problems/Problem 1"

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+ | ==Solution 2== | ||

+ | The boy buys <math>3</math> oranges for <math>10</math> cents. He sells them at <math>5</math> for <math>20</math>. So, he buys <math>15</math> for <math>50</math> cents and sells them a <math>15</math> for <math>60</math> cents, so he makes <math>10</math> cents of profit on every <math>5</math> oranges. To make <math>100</math> cents of profit, he needs to sell <math>10\cdot 5</math>, or <math>50</math> oranges. |

## Revision as of 20:10, 1 April 2017

A boy buys oranges at for cents. He will sell them at for cents. In order to make a profit of , he must sell:

## Solution

The boy buys oranges for cents or orange for cents. He sells them at cents each. That means for every orange he sells, he makes a profit of cents.

To make a profit of cents, he needs to sell

~mathsolver101

## Solution 2

The boy buys oranges for cents. He sells them at for . So, he buys for cents and sells them a for cents, so he makes cents of profit on every oranges. To make cents of profit, he needs to sell , or oranges.