Difference between revisions of "1953 AHSME Problems/Problem 1"
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| + | ==Solution 2== | ||
| + | The boy buys <math>3</math> oranges for <math>10</math> cents. He sells them at <math>5</math> for <math>20</math>. So, he buys <math>15</math> for <math>50</math> cents and sells them a <math>15</math> for <math>60</math> cents, so he makes <math>10</math> cents of profit on every <math>5</math> oranges. To make <math>100</math> cents of profit, he needs to sell <math>10\cdot 5</math>, or <math>50</math> oranges. | ||
Revision as of 20:10, 1 April 2017
A boy buys oranges at 
for 
cents. He will sell them at 
for 
cents. In order to make a profit of 
, he must sell:
Solution
The boy buys oranges for cents or 
orange for 
cents. He sells them at 
cents each.
That means for every orange he sells, he makes a profit of 
cents.
To make a profit of 
cents, he needs to sell 
~mathsolver101
Solution 2
The boy buys oranges for cents. He sells them at for . So, he buys 
for 
cents and sells them a for 
cents, so he makes cents of profit on every oranges. To make cents of profit, he needs to sell 
, or oranges.
