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Difference between revisions of "1953 AHSME Problems/Problem 10"

(Created page with "== Problem == The number of revolutions of a wheel, with fixed center and with an outside diameter of <math>6</math> feet, required to cause a point on the rim to go one mile...")
 
 
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We know that the radius of the wheel is <math>3</math> feet, so the total circumference of the wheel is <math>6\pi</math> feet. We also know that one mile is equivalent to <math>5280</math> feet. It takes <math>\frac{5280}{6\pi}</math> revolutions for any one point on the wheel to travel a mile. Simplifying, we find that the answer is <math>\boxed{\textbf{(C) } \frac{880}{\pi}}</math>.
 
We know that the radius of the wheel is <math>3</math> feet, so the total circumference of the wheel is <math>6\pi</math> feet. We also know that one mile is equivalent to <math>5280</math> feet. It takes <math>\frac{5280}{6\pi}</math> revolutions for any one point on the wheel to travel a mile. Simplifying, we find that the answer is <math>\boxed{\textbf{(C) } \frac{880}{\pi}}</math>.
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==See Also==
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{{AHSME 50p box|year=1953|num-b=9|num-a=11}}
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[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 20:47, 1 April 2017

Problem

The number of revolutions of a wheel, with fixed center and with an outside diameter of $6$ feet, required to cause a point on the rim to go one mile is:

$\textbf{(A)}\ 880 \qquad\textbf{(B)}\ \frac{440}{\pi} \qquad\textbf{(C)}\ \frac{880}{\pi} \qquad\textbf{(D)}\ 440\pi\qquad\textbf{(E)}\ \text{none of these}$

Solution

We know that the radius of the wheel is $3$ feet, so the total circumference of the wheel is $6\pi$ feet. We also know that one mile is equivalent to $5280$ feet. It takes $\frac{5280}{6\pi}$ revolutions for any one point on the wheel to travel a mile. Simplifying, we find that the answer is $\boxed{\textbf{(C) } \frac{880}{\pi}}$.


See Also

1953 AHSC (Problems • Answer Key • Resources)
Preceded by
Problem 9 		Followed by
Problem 11
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50
All AHSME Problems and Solutions

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